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Centripetal force

Physics • Circular Motion & Gravitation • Transitional Reasoning • 9 questions

Centripetal force Transitional Reasoning Download PDF

Physics · Forces & Newton's Laws · Physics · Circular Motion & Gravitation

9 Physics practice questions on Centripetal force. Questions that build towards applied reasoning.

Questions

  1. 1.

    An orbital mechanics team monitors two scientific satellites, AA and BB, in stable circular orbits around a planet. Satellite BB orbits at a radius four times that of Satellite AA, such that rB=4rAr_B = 4r_A. Given that the planet's gravitational force provides the necessary centripetal force for circular motion, which of the following correctly compares the orbital speed vBv_B and centripetal acceleration aBa_B of Satellite BB to those of Satellite AA?

    • A) vB=12vAv_B = \frac{1}{2}v_A and aB=116aAa_B = \frac{1}{16}a_A
    • B) vB=12vAv_B = \frac{1}{2}v_A and aB=14aAa_B = \frac{1}{4}a_A
    • C) vB=14vAv_B = \frac{1}{4}v_A and aB=116aAa_B = \frac{1}{16}a_A
    • D) vB=2vAv_B = 2v_A and aB=12aAa_B = \frac{1}{2}a_A
  2. 2.

    A student investigates uniform circular motion using an air-table apparatus where a puck of mass mm glides without friction along a horizontal circle of radius rr. The puck is connected to a light cord that passes through a small frictionless hole at the center of the table and supports a hanging counterweight of mass MM. If the counterweight remains completely stationary while the puck circles smoothly, which expression correctly gives the required orbital speed vv of the puck?

    • A) v=Mgrmv = \sqrt{\frac{M g r}{m}}
    • B) v=mgrMv = \sqrt{\frac{m g r}{M}}
    • C) v=(M+m)grmv = \sqrt{\frac{(M + m) g r}{m}}
    • D) v=Mgmrv = \sqrt{\frac{M g}{m r}}
  3. 3.

    A civil engineering team designs an exit ramp as a circular curve of radius RR banked at an angle θ\theta relative to the horizontal. On an icy day with negligible tire-road friction, a car of mass mm safely negotiates the curve at the rated design speed without sliding up or down the embankment. Which of the following correctly describes the magnitude of the normal force FNF_N exerted by the road on the car relative to its weight mgmg, along with the correct physical reasoning?

    • A) FN=mgcos⁡θF_N = \frac{mg}{\cos\theta} (so FN>mgF_N > mg), because the vertical component of the normal force must balance the car's full weight while its horizontal component supplies the centripetal acceleration.
    • B) FN=mgcos⁡θF_N = mg \cos\theta (so FN<mgF_N < mg), because the normal force acts perpendicular to the incline and only needs to support the perpendicular component of gravity.
    • C) FN=mgF_N = mg, because the centripetal acceleration is purely horizontal and does not affect the magnitude of the normal force required to support the car.
    • D) FN=mgsin⁡θF_N = \frac{mg}{\sin\theta} (so FN>mgF_N > mg), because the sine component of the normal force balances gravity while the cosine component supplies the centripetal acceleration.
  4. 4.

    Two identical small blocks, XX and YY, rest on a flat, horizontal turntable at distances rr and 2r2r from the central rotational axis, respectively. The coefficient of static friction between each block and the turntable surface is identical. As the turntable slowly increases its angular speed from rest, which block will slip first, and why?

    • A) Block XX slips first because the required centripetal force is inversely proportional to the radius of circular motion at a given angular speed.
    • B) Block YY slips first because the required centripetal force is directly proportional to the radius at a shared angular speed, causing it to exceed the maximum static friction first.
    • C) Both blocks slip simultaneously because the maximum static friction force depends only on mass and the coefficient of friction, which are identical for both blocks.
    • D) Block XX slips first because it experiences a greater tangential acceleration during the rotational spin-up than block YY.
  5. 5.

    A small robotic cart of mass mm moves in a horizontal circle at a constant angular speed ω\omega on a frictionless tabletop. The cart is tethered to a fixed central peg by a light horizontal spring with spring constant kk and an unstretched length L0L_0. If the spring stretches to establish a circular path of radius RR under the condition k>mω2k > m\omega^2, which of the following expressions correctly determines RR?

    • A) R=kL0k−mω2R = \frac{k L_0}{k - m\omega^2}
    • B) R=kL0k+mω2R = \frac{k L_0}{k + m\omega^2}
    • C) R=mω2L0k−mω2R = \frac{m\omega^2 L_0}{k - m\omega^2}
    • D) R=(k−mω2)L0kR = \frac{(k - m\omega^2)L_0}{k}
  6. 6.

    An automotive safety team tests a vehicle of mass mm as it drives over the crest of a hill modeled as a circular arc of radius RR. While passing the highest point of the crest at a constant speed, an onboard accelerometer records a downward centripetal acceleration of magnitude 0.36g0.36g. Assuming the acceleration due to gravity is gg, what is the magnitude of the normal force exerted by the road on the vehicle at this point?

    • A) 0.36mg0.36mg
    • B) 1.36mg1.36mg
    • C) 0.64mg0.64mg
    • D) 0.80mg0.80mg
  7. 7.

    In an amusement park rotor ride, riders stand against the inner vertical wall of a hollow cylinder of radius RR that rotates at a constant angular velocity about its central vertical axis. Once the ride reaches operating speed, the floor beneath the riders drops away, yet each rider remains held firmly against the wall without sliding downward. Which of the following statements correctly identifies the physical origin of the centripetal force and the force that prevents the rider from falling?

    • A) The centripetal force is provided by static friction directed tangent to the wall, while the inward normal force balances gravity.
    • B) The centripetal force is provided by an outward centrifugal force, while an upward normal force balances gravity.
    • C) The centripetal force is provided by the inward normal force exerted by the wall, while upward static friction balances gravity.
    • D) The centripetal force is provided by gravity acting toward the center of rotation, while upward kinetic friction supports the rider.
  8. 8.

    In a physics laboratory investigation, a student sets up a conical pendulum by suspending a small bob of mass mm from a light cord. When set into motion, the bob travels in a horizontal circle of radius rr at a constant speed while the cord sweeps out a cone, maintaining a constant angle θ\theta relative to the vertical. Which of the following expressions and physical explanations correctly identifies the magnitude of the centripetal force FcF_c acting on the bob?

    • A) Fc=mgcos⁡θF_c = mg \cos\theta, because the component of the bob's weight perpendicular to the cord provides the inward acceleration.
    • B) Fc=mgtan⁡θF_c = mg \tan\theta, because the vertical component of the cord tension balances gravity while the horizontal component acts as the inward net force.
    • C) Fc=mgsin⁡θF_c = mg \sin\theta, because the component of the gravitational force along the tilt of the cord pulls the bob toward the center of the circle.
    • D) Fc=mgsin⁡θF_c = \frac{mg}{\sin\theta}, because the entire tension along the cord must be directed inward to maintain the circular path.
  9. 9.

    A roller coaster car of mass mm travels along the inside of a vertical circular loop of radius RR. At the exact top of the loop, the car moves at the minimum threshold speed v=gRv = \sqrt{gR} required to complete the circle without losing contact with the track. Which statement correctly identifies the forces acting on the car and their role at this highest point?

    • A) The track exerts an upward normal force that exactly balances the downward gravitational force, keeping the car in dynamic equilibrium.
    • B) An independent inward centripetal force acts downward in addition to gravity and the normal force to maintain circular motion.
    • C) Gravitational force alone provides the required centripetal acceleration, resulting in a normal force of zero exerted by the track.
    • D) The track exerts its maximum downward normal force on the car to counteract outward centrifugal inertia.