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Empirical formulas

Chemistry • The Mole • Transitional Reasoning • 5 questions

Empirical formulas Transitional Reasoning Download PDF

Chemistry · The Mole & Stoichiometry · Chemistry · The Mole

5 Chemistry practice questions on Empirical formulas. Questions that build towards applied reasoning.

Questions

  1. 1.

    To identify an iron oxide present in a mineral sample, an analyst heats a 3.48 g sample of the oxide in a tube furnace under a steady stream of dry hydrogen gas until it is completely reduced to 2.52 g of pure iron metal. Assuming all oxygen is removed as water vapor and using molar masses of Fe=56.0 g/mol\text{Fe} = 56.0\text{ g/mol} and O=16.0 g/mol\text{O} = 16.0\text{ g/mol}, what is the empirical formula of this iron oxide?

    • A) FeO\text{FeO}
    • B) Fe2O3\text{Fe}_2\text{O}_3
    • C) Fe3O2\text{Fe}_3\text{O}_2
    • D) Fe3O4\text{Fe}_3\text{O}_4
  2. 2.

    A chemistry student investigates the thermal decomposition of a pure solid salt containing potassium, chlorine, and oxygen. Heating a 2.45 g sample strongly drives off all the oxygen as gas, leaving behind 1.49 g of solid potassium chloride (KClKCl). Given the molar masses of K=39.1 g/molK = 39.1\text{ g/mol}, Cl=35.5 g/molCl = 35.5\text{ g/mol}, and O=16.0 g/molO = 16.0\text{ g/mol}, what is the empirical formula of the original salt?

    • A) KClO3KClO_3
    • B) KClO4KClO_4
    • C) KClO2KClO_2
    • D) KClOKClO
  3. 3.

    Industrial catalysts used in the Contact process to manufacture sulfuric acid rely on an active vanadium oxide compound. Quantitative elemental analysis indicates that this oxide contains 56.0% vanadium and 44.0% oxygen by mass. Given that the molar mass of vanadium is 51.0 g/mol and that of oxygen is 16.0 g/mol, which of the following is the empirical formula of the compound?

    • A) VOVO
    • B) VO2VO_2
    • C) V2O3V_2O_3
    • D) V2O5V_2O_5
  4. 4.

    In an investigation to determine the empirical formula of an oxide of phosphorus, a student completely reacts a 4.34 g sample of pure phosphorus with excess oxygen gas. The reaction yields 9.94 g of a single solid phosphorus oxide product. Given the molar masses of phosphorus (31.0 g/mol) and oxygen (16.0 g/mol), what is the empirical formula of this compound?

    • A) PO3PO_3
    • B) P2O5P_2O_5
    • C) P2O3P_2O_3
    • D) PO2PO_2
  5. 5.

    A 4.60 g sample of a liquid fuel containing only carbon, hydrogen, and oxygen undergoes complete combustion, yielding 8.80 g of CO2CO_2 and 5.40 g of H2OH_2O. Using molar masses of 12.0 g/mol for carbon, 1.0 g/mol for hydrogen, and 16.0 g/mol for oxygen, which empirical formula represents this compound?

    • A) C2H3OC_2H_3O
    • B) C2H6OC_2H_6O
    • C) C2H4OC_2H_4O
    • D) C3H8O2C_3H_8O_2