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Empirical formulas

Chemistry • The Mole • Knowledge-Based • 5 questions

Empirical formulas Knowledge-Based Download PDF

Chemistry · The Mole & Stoichiometry · Chemistry · The Mole

5 Chemistry practice questions on Empirical formulas. Questions that assess core concepts and understanding.

Questions

  1. 1.

    A 2.16 g sample of a hydrocarbon is completely burned in excess oxygen to produce 7.04 g of CO2\text{CO}_2 and 2.16 g of H2O\text{H}_2\text{O}. What is the empirical formula of the hydrocarbon? (Molar masses: C=12.0 g/mol\text{C} = 12.0\text{ g/mol}, H=1.0 g/mol\text{H} = 1.0\text{ g/mol}, O=16.0 g/mol\text{O} = 16.0\text{ g/mol})

    • A) CH2\text{CH}_2
    • B) C2H3\text{C}_2\text{H}_3
    • C) C3H8\text{C}_3\text{H}_8
    • D) C4H3\text{C}_4\text{H}_3
  2. 2.

    A mineral sample contains 32.4% sodium, 22.6% sulfur, and 45.0% oxygen by mass. What is the empirical formula of this compound? (Molar masses: Na = 23.0 g/mol, S = 32.1 g/mol, O = 16.0 g/mol)

    • A) NaSO4
    • B) Na2SO4
    • C) Na2SO3
    • D) NaSO2
  3. 3.

    A 4.79 g sample of titanium reacts completely with chlorine gas to produce 18.99 g of a titanium chloride compound. What is the empirical formula of this compound? (Molar masses: Ti = 47.9 g/mol, Cl = 35.5 g/mol)

    • A) TiCl3\text{TiCl}_3
    • B) TiCl4\text{TiCl}_4
    • C) TiCl2\text{TiCl}_2
    • D) Ti2Cl5\text{Ti}_2\text{Cl}_5
  4. 4.

    A 4.60 g sample of a compound containing only carbon, hydrogen, and oxygen contains 2.40 g of carbon and 0.60 g of hydrogen. What is the empirical formula of this compound? (Molar masses: C = 12.0 g/mol, H = 1.0 g/mol, O = 16.0 g/mol)

    • A) C2H6O\text{C}_2\text{H}_6\text{O}
    • B) CH3O\text{CH}_3\text{O}
    • C) CH2O\text{CH}_2\text{O}
    • D) C2H4O\text{C}_2\text{H}_4\text{O}
  5. 5.

    A sample of an iron oxide contains 69.9% iron and 30.1% oxygen by mass. What is the empirical formula of this compound? (Molar masses: Fe = 55.8 g/mol, O = 16.0 g/mol)

    • A) Fe2O3\text{Fe}_2\text{O}_3
    • B) FeO\text{FeO}
    • C) Fe3O4\text{Fe}_3\text{O}_4
    • D) FeO2\text{FeO}_2