Molecular formulas Transitional Reasoning Download PDF
5 Chemistry practice questions on Molecular formulas. Questions that build towards applied reasoning.
Questions
- 1.
An analytical chemist investigating an industrial sulfur pollutant determines that its empirical formula is . Complete combustion of a 0.200 mol sample of this pure compound in excess oxygen produces 17.6 g of carbon dioxide gas () alongside sulfur dioxide and water vapor. What is the molecular formula of this pollutant? (Atomic masses: , , , )
- 2.
Complete combustion of a 0.450 g sample of an unknown organic compound containing only carbon, hydrogen, and oxygen produces 0.660 g of carbon dioxide and 0.270 g of water. In a separate experiment, mass spectrometry determines that the molar mass of the compound is 90.0 g/mol. What is the molecular formula of this compound? (Atomic masses: , , )
- 3.
A synthetic chemist analyzes a solid oxide of phosphorus produced by burning pure phosphorus in dry air. Elemental analysis shows that the oxide consists of 43.6% phosphorus and 56.4% oxygen by mass. In a separate measurement, a sample containing molecules of this compound has a mass of 7.10 g. What is the molecular formula of the oxide? (Atomic masses: , ; Avogadro's number: )
- 4.
An industrial chemist analyzes an unknown gaseous hydrocarbon emitted during polymer manufacturing and finds it consists of 85.6% carbon and 14.4% hydrogen by mass. In a separate physical measurement at standard temperature and pressure (STP), a 5.60 L sample of this pure gas has a mass of 14.0 g. What is the molecular formula of this hydrocarbon? (Molar masses: C = 12.0 g/mol, H = 1.0 g/mol; molar volume of gas at STP = 22.4 L/mol)
- 5.
A chemist analyzes an unknown liquid used as an industrial flavoring agent and determines that its empirical formula is . In a subsequent vapor analysis, a 0.250 mol sample of the pure compound is found to have a mass of 22.0 g. What is the molecular formula of this compound? (Atomic masses: C = 12.0 g/mol, H = 1.0 g/mol, O = 16.0 g/mol)

