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Molecular formulas

Chemistry • The Mole • Transitional Reasoning • 5 questions

Molecular formulas Transitional Reasoning Download PDF

Chemistry · The Mole & Stoichiometry · Chemistry · The Mole

5 Chemistry practice questions on Molecular formulas. Questions that build towards applied reasoning.

Questions

  1. 1.

    An analytical chemist investigating an industrial sulfur pollutant determines that its empirical formula is CH3S\text{CH}_3\text{S}. Complete combustion of a 0.200 mol sample of this pure compound in excess oxygen produces 17.6 g of carbon dioxide gas (CO2\text{CO}_2) alongside sulfur dioxide and water vapor. What is the molecular formula of this pollutant? (Atomic masses: C=12.0 g/mol\text{C} = 12.0\text{ g/mol}, H=1.0 g/mol\text{H} = 1.0\text{ g/mol}, O=16.0 g/mol\text{O} = 16.0\text{ g/mol}, S=32.1 g/mol\text{S} = 32.1\text{ g/mol})

    • A) CH3S\text{CH}_3\text{S}
    • B) C2H6S2\text{C}_2\text{H}_6\text{S}_2
    • C) C3H9S3\text{C}_3\text{H}_9\text{S}_3
    • D) C4H12S4\text{C}_4\text{H}_{12}\text{S}_4
  2. 2.

    Complete combustion of a 0.450 g sample of an unknown organic compound containing only carbon, hydrogen, and oxygen produces 0.660 g of carbon dioxide and 0.270 g of water. In a separate experiment, mass spectrometry determines that the molar mass of the compound is 90.0 g/mol. What is the molecular formula of this compound? (Atomic masses: C=12.0 g/mol\text{C} = 12.0\text{ g/mol}, H=1.0 g/mol\text{H} = 1.0\text{ g/mol}, O=16.0 g/mol\text{O} = 16.0\text{ g/mol})

    • A) CH2O\text{CH}_2\text{O}
    • B) C2H4O2\text{C}_2\text{H}_4\text{O}_2
    • C) C6H12O6\text{C}_6\text{H}_{12}\text{O}_6
    • D) C3H6O3\text{C}_3\text{H}_6\text{O}_3
  3. 3.

    A synthetic chemist analyzes a solid oxide of phosphorus produced by burning pure phosphorus in dry air. Elemental analysis shows that the oxide consists of 43.6% phosphorus and 56.4% oxygen by mass. In a separate measurement, a sample containing 1.505×10221.505 \times 10^{22} molecules of this compound has a mass of 7.10 g. What is the molecular formula of the oxide? (Atomic masses: P=31.0 g/mol\text{P} = 31.0\text{ g/mol}, O=16.0 g/mol\text{O} = 16.0\text{ g/mol}; Avogadro's number: NA=6.02×1023 mol−1N_A = 6.02 \times 10^{23}\text{ mol}^{-1})

    • A) P4O10\text{P}_4\text{O}_{10}
    • B) P2O5\text{P}_2\text{O}_5
    • C) P4O6\text{P}_4\text{O}_6
    • D) P2O3\text{P}_2\text{O}_3
  4. 4.

    An industrial chemist analyzes an unknown gaseous hydrocarbon emitted during polymer manufacturing and finds it consists of 85.6% carbon and 14.4% hydrogen by mass. In a separate physical measurement at standard temperature and pressure (STP), a 5.60 L sample of this pure gas has a mass of 14.0 g. What is the molecular formula of this hydrocarbon? (Molar masses: C = 12.0 g/mol, H = 1.0 g/mol; molar volume of gas at STP = 22.4 L/mol)

    • A) C3H6\text{C}_3\text{H}_6
    • B) C4H8\text{C}_4\text{H}_8
    • C) C5H10\text{C}_5\text{H}_{10}
    • D) C6H12\text{C}_6\text{H}_{12}
  5. 5.

    A chemist analyzes an unknown liquid used as an industrial flavoring agent and determines that its empirical formula is C2H4O\text{C}_2\text{H}_4\text{O}. In a subsequent vapor analysis, a 0.250 mol sample of the pure compound is found to have a mass of 22.0 g. What is the molecular formula of this compound? (Atomic masses: C = 12.0 g/mol, H = 1.0 g/mol, O = 16.0 g/mol)

    • A) C2H4O\text{C}_2\text{H}_4\text{O}
    • B) C3H6O2\text{C}_3\text{H}_6\text{O}_2
    • C) C4H8O2\text{C}_4\text{H}_8\text{O}_2
    • D) C6H12O3\text{C}_6\text{H}_{12}\text{O}_3