PDF Downloads

Cross product

Physics • Math Tools for Physics • Transitional Reasoning • 5 questions

Cross product Transitional Reasoning Download PDF

Physics · Introduction to Physics · Physics · Math Tools for Physics

5 Physics practice questions on Cross product. Questions that build towards applied reasoning.

Questions

  1. 1.

    In a physics laboratory experiment, a tracking system monitors an object of mass 2.0 kg moving in the xy-plane. At a specific moment, the object's position vector relative to the coordinate origin is r⃗=(3.0i^+4.0j^) m\vec{r} = (3.0\hat{i} + 4.0\hat{j})\text{ m} and its velocity vector is v⃗=(5.0i^+2.0j^) m/s\vec{v} = (5.0\hat{i} + 2.0\hat{j})\text{ m/s}. The angular momentum vector with respect to the origin is defined by the cross product L⃗=r⃗×p⃗\vec{L} = \vec{r} \times \vec{p}, where p⃗=mv⃗\vec{p} = m\vec{v} is the linear momentum. What is the angular momentum vector L⃗\vec{L} of the object, and along which axis does it point?

    • A) L⃗=+28k^ kg⋅m2/s\vec{L} = +28\hat{k}\text{ kg}\cdot\text{m}^2/\text{s}, pointing along the positive z-axis
    • B) L⃗=−14k^ kg⋅m2/s\vec{L} = -14\hat{k}\text{ kg}\cdot\text{m}^2/\text{s}, pointing along the negative z-axis
    • C) L⃗=−28k^ kg⋅m2/s\vec{L} = -28\hat{k}\text{ kg}\cdot\text{m}^2/\text{s}, pointing along the negative z-axis
    • D) L⃗=+52k^ kg⋅m2/s\vec{L} = +52\hat{k}\text{ kg}\cdot\text{m}^2/\text{s}, pointing along the positive z-axis
  2. 2.

    In an automated manufacturing system, a robotic probe pivots in the xy-plane about the origin with an instantaneous angular velocity of ω⃗=4.0k^ rad/s\vec{\omega} = 4.0\hat{k}\text{ rad/s}. The tip of the probe is currently located at position r⃗=(0.60i^+0.80j^) m\vec{r} = (0.60\hat{i} + 0.80\hat{j})\text{ m}. The linear velocity vector of the probe tip is determined by the cross product relation v⃗=ω⃗×r⃗\vec{v} = \vec{\omega} \times \vec{r}. Which of the following correctly gives the linear velocity vector v⃗\vec{v} and the corresponding linear speed ∣v⃗∣|\vec{v}| of the probe tip?

    • A) v⃗=(−3.2i^+2.4j^) m/s\vec{v} = (-3.2\hat{i} + 2.4\hat{j})\text{ m/s} and ∣v⃗∣=4.0 m/s|\vec{v}| = 4.0\text{ m/s}
    • B) v⃗=(3.2i^+2.4j^) m/s\vec{v} = (3.2\hat{i} + 2.4\hat{j})\text{ m/s} and ∣v⃗∣=4.0 m/s|\vec{v}| = 4.0\text{ m/s}
    • C) v⃗=(2.4i^−3.2j^) m/s\vec{v} = (2.4\hat{i} - 3.2\hat{j})\text{ m/s} and ∣v⃗∣=4.0 m/s|\vec{v}| = 4.0\text{ m/s}
    • D) v⃗=(−3.2i^−2.4j^) m/s\vec{v} = (-3.2\hat{i} - 2.4\hat{j})\text{ m/s} and ∣v⃗∣=5.6 m/s|\vec{v}| = 5.6\text{ m/s}
  3. 3.

    To model the solar energy collected by a planar sensor on an oceanographic buoy, researchers define two triangular boundary edges from a shared vertex using displacement vectors a⃗=6i^ cm\vec{a} = 6\hat{i}\text{ cm} and b⃗=(2i^+5j^) cm\vec{b} = (2\hat{i} + 5\hat{j})\text{ cm}. The geometric area of this triangular facet is given by 12∣a⃗×b⃗∣\frac{1}{2}|\vec{a} \times \vec{b}|, while its normal orientation vector is defined by the cross product a⃗×b⃗\vec{a} \times \vec{b}. Which of the following correctly provides the area of the sensor facet and the direction of its orientation vector?

    • A) 15 cm215\text{ cm}^2, pointing along the +k^+\hat{k} direction
    • B) 30 cm230\text{ cm}^2, pointing along the +k^+\hat{k} direction
    • C) 15 cm215\text{ cm}^2, pointing along the −k^-\hat{k} direction
    • D) 30 cm230\text{ cm}^2, pointing along the −k^-\hat{k} direction
  4. 4.

    An aerospace engineering team models the rotational orientation of a satellite using two structural displacement vectors, A⃗=(2i^+j^−3k^) m\vec{A} = (2\hat{i} + \hat{j} - 3\hat{k})\text{ m} and B⃗=(−i^+4k^) m\vec{B} = (-\hat{i} + 4\hat{k})\text{ m}. To define a normal axis for an instrument panel, the team computes the vector cross product C⃗=A⃗×B⃗\vec{C} = \vec{A} \times \vec{B}. Which of the following correctly gives the resulting vector C⃗\vec{C} and describes its geometric relationship to vectors A⃗\vec{A} and B⃗\vec{B}?

    • A) C⃗=(4i^+11j^+k^) m2\vec{C} = (4\hat{i} + 11\hat{j} + \hat{k})\text{ m}^2, and it lies within the plane formed by A⃗\vec{A} and B⃗\vec{B}
    • B) C⃗=(−4i^+5j^−k^) m2\vec{C} = (-4\hat{i} + 5\hat{j} - \hat{k})\text{ m}^2, and it is perpendicular only to A⃗\vec{A}
    • C) C⃗=(4i^+5j^+k^) m2\vec{C} = (4\hat{i} + 5\hat{j} + \hat{k})\text{ m}^2, and it is parallel to B⃗\vec{B}
    • D) C⃗=(4i^−5j^+k^) m2\vec{C} = (4\hat{i} - 5\hat{j} + \hat{k})\text{ m}^2, and it is perpendicular to both A⃗\vec{A} and B⃗\vec{B}
  5. 5.

    A flight controller calculates the corrective steering vector τ⃗=r⃗×F⃗\vec{\tau} = \vec{r} \times \vec{F} acting on a drone maneuvered in a horizontal plane. The displacement vector r⃗\vec{r} has a magnitude of 5.0 m pointing along the positive x-axis, while the applied thrust vector F⃗\vec{F} has a magnitude of 8.0 N in the xy-plane oriented at an angle of 150° measured counterclockwise from the positive x-axis. Which of the following correctly gives the magnitude and direction of τ⃗\vec{\tau}, as well as the consequence of reversing the operation to F⃗×r⃗\vec{F} \times \vec{r}?

    • A) Magnitude is 34.6 N·m in the +z-direction, and F⃗×r⃗\vec{F} \times \vec{r} produces an identical vector because vector multiplication is commutative.
    • B) Magnitude is 20 N·m in the +y-direction, and F⃗×r⃗\vec{F} \times \vec{r} produces −20j^-20\hat{j} N·m because the resulting vector must stay in the same plane.
    • C) Magnitude is 20 N·m in the +z-direction, and F⃗×r⃗\vec{F} \times \vec{r} produces −20k^-20\hat{k} N·m because the cross product is anti-commutative.
    • D) Magnitude is 20 N·m in the −z-direction, and F⃗×r⃗\vec{F} \times \vec{r} produces +20k^+20\hat{k} N·m because curling fingers from r⃗\vec{r} to F⃗\vec{F} points downward.