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Cross product

Physics • Math Tools for Physics • Knowledge-Based • 6 questions

Cross product Knowledge-Based Download PDF

Physics · Introduction to Physics · Physics · Math Tools for Physics

6 Physics practice questions on Cross product. Questions that assess core concepts and understanding.

Questions

  1. 1.

    Two vectors A⃗=4i^\vec{A} = 4\hat{i} and B⃗=2i^+5j^\vec{B} = 2\hat{i} + 5\hat{j} define adjacent sides of a parallelogram. What is the area of this parallelogram?

    • A) 20 square units
    • B) 10 square units
    • C) 8 square units
    • D) 28 square units
  2. 2.

    For two non-zero vectors A⃗\vec{A} and B⃗\vec{B}, the magnitude of their cross product is equal to their scalar product such that ∣A⃗×B⃗∣=A⃗⋅B⃗|\vec{A} \times \vec{B}| = \vec{A} \cdot \vec{B}. What is the angle between the two vectors?

    • A) 30∘30^\circ
    • B) 45∘45^\circ
    • C) 60∘60^\circ
    • D) 90∘90^\circ
  3. 3.

    Which of the following Cartesian unit vector cross products results in −i^-\hat{i}?

    • A) j^×k^\hat{j} \times \hat{k}
    • B) i^×k^\hat{i} \times \hat{k}
    • C) j^×i^\hat{j} \times \hat{i}
    • D) k^×j^\hat{k} \times \hat{j}
  4. 4.

    Which of the following statements is always true regarding the cross product of two non-zero, non-collinear vectors A⃗\vec{A} and B⃗\vec{B}?

    • A) The resulting vector lies within the plane formed by A⃗\vec{A} and B⃗\vec{B}.
    • B) The resulting vector is perpendicular to both A⃗\vec{A} and B⃗\vec{B}.
    • C) Reversing the order of vectors preserves the result such that A⃗×B⃗=B⃗×A⃗\vec{A} \times \vec{B} = \vec{B} \times \vec{A}.
    • D) The magnitude of the cross product reaches its maximum value when A⃗\vec{A} and B⃗\vec{B} are parallel.
  5. 5.

    Two vectors A⃗\vec{A} and B⃗\vec{B} have magnitudes of 8 units and 5 units, respectively. If the angle between them is 30°, what is the magnitude of their cross product, ∣A⃗×B⃗∣|\vec{A} \times \vec{B}|?

    • A) 20 units
    • B) 20320\sqrt{3} units
    • C) 40 units
    • D) 10 units
  6. 6.

    Given the vectors u⃗=2i^−j^+3k^\vec{u} = 2\hat{i} - \hat{j} + 3\hat{k} and v⃗=i^+2j^−k^\vec{v} = \hat{i} + 2\hat{j} - \hat{k}, what is the cross product u⃗×v⃗\vec{u} \times \vec{v}?

    • A) 5i^−5j^−5k^5\hat{i} - 5\hat{j} - 5\hat{k}
    • B) −5i^−5j^+5k^-5\hat{i} - 5\hat{j} + 5\hat{k}
    • C) −5i^+5j^+5k^-5\hat{i} + 5\hat{j} + 5\hat{k}
    • D) 7i^+j^+3k^7\hat{i} + \hat{j} + 3\hat{k}