Empirical formulas Knowledge-Based Practice

Chemistry · The Mole & Stoichiometry · Chemistry · The Mole

5 Chemistry practice questions on Empirical formulas. Questions that assess core concepts and understanding.

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Questions

  1. 1.

    Which of the following pairs of compounds have the same empirical formula?

    • A) C2H6\text{C}_2\text{H}_6 and C3H6\text{C}_3\text{H}_6
    • B) NO2\text{NO}_2 and N2O5\text{N}_2\text{O}_5
    • C) C2H2\text{C}_2\text{H}_2 and C6H6\text{C}_6\text{H}_6
    • D) H2O\text{H}_2\text{O} and H2O2\text{H}_2\text{O}_2
  2. 2.

    A 1.38 g sample of an unknown organic compound containing only carbon, hydrogen, and oxygen is burned completely in oxygen, yielding 2.64 g of CO2\text{CO}_2 and 1.62 g of H2O\text{H}_2\text{O}. What is the empirical formula of the compound? (Molar masses: C=12.0 g/mol\text{C} = 12.0\text{ g/mol}, H=1.0 g/mol\text{H} = 1.0\text{ g/mol}, O=16.0 g/mol\text{O} = 16.0\text{ g/mol})

    • A) CH2O\text{CH}_2\text{O}
    • B) C2H4O\text{C}_2\text{H}_4\text{O}
    • C) C3H8O\text{C}_3\text{H}_8\text{O}
    • D) C2H6O\text{C}_2\text{H}_6\text{O}
  3. 3.

    When a 4.86 g sample of magnesium metal is heated in pure nitrogen gas, it completely reacts to produce 6.73 g of a magnesium nitride compound. What is the empirical formula of this compound? (Molar masses: Mg = 24.3 g/mol, N = 14.0 g/mol)

    • A) MgN\text{MgN}
    • B) Mg3N2\text{Mg}_3\text{N}_2
    • C) Mg2N3\text{Mg}_2\text{N}_3
    • D) MgN2\text{MgN}_2
  4. 4.

    A compound consists of 40.0% carbon, 6.7% hydrogen, and 53.3% oxygen by mass. What is the empirical formula of this compound? (Molar masses: C=12.0 g/mol\text{C} = 12.0\text{ g/mol}, H=1.0 g/mol\text{H} = 1.0\text{ g/mol}, O=16.0 g/mol\text{O} = 16.0\text{ g/mol})

    • A) CHO\text{CHO}
    • B) CHO2\text{CHO}_2
    • C) CH2O\text{CH}_2\text{O}
    • D) C2H5O\text{C}_2\text{H}_5\text{O}
  5. 5.

    A sample of an iron oxide contains 69.9% iron and 30.1% oxygen by mass. What is the empirical formula of this compound? (Molar masses: Fe=55.8 g/mol\text{Fe} = 55.8\text{ g/mol}, O=16.0 g/mol\text{O} = 16.0\text{ g/mol})

    • A) FeO\text{FeO}
    • B) FeO2\text{FeO}_2
    • C) Fe3O4\text{Fe}_3\text{O}_4
    • D) Fe2O3\text{Fe}_2\text{O}_3

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