Avogadro's number Knowledge-Based Practice

Chemistry · The Mole & Stoichiometry · Chemistry · The Mole

5 Chemistry practice questions on Avogadro's number. Questions that assess core concepts and understanding.

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Questions

  1. 1.

    Which of the following pure substance samples contains the greatest total number of molecules? (Molar masses: CH4=16.04 g/mol\text{CH}_4 = 16.04\text{ g/mol}, O2=32.00 g/mol\text{O}_2 = 32.00\text{ g/mol}, CO2=44.01 g/mol\text{CO}_2 = 44.01\text{ g/mol}, SO2=64.07 g/mol\text{SO}_2 = 64.07\text{ g/mol})

    • A) 10.0 g of CO210.0\text{ g of }\text{CO}_2
    • B) 10.0 g of O210.0\text{ g of }\text{O}_2
    • C) 10.0 g of CH410.0\text{ g of }\text{CH}_4
    • D) 10.0 g of SO210.0\text{ g of }\text{SO}_2
  2. 2.

    What is the total number of ions present in a 0.200 mol sample of pure solid aluminum oxide, Al2O3\text{Al}_2\text{O}_3? (Avogadro's constant, NA=6.022×1023 mol−1N_{\text{A}} = 6.022 \times 10^{23}\text{ mol}^{-1})

    • A) 1.20×10231.20 \times 10^{23}
    • B) 6.02×10236.02 \times 10^{23}
    • C) 2.41×10232.41 \times 10^{23}
    • D) 3.61×10233.61 \times 10^{23}
  3. 3.

    What is the mass, in grams, of a single molecule of nitrogen gas, N2\text{N}_2? (Molar mass of N2=28.02 g/mol\text{N}_2 = 28.02\text{ g/mol}; Avogadro's constant, NA=6.022×1023 mol−1N_A = 6.022 \times 10^{23}\text{ mol}^{-1})

    • A) 1.69×1025 g1.69 \times 10^{25}\text{ g}
    • B) 2.33×10−23 g2.33 \times 10^{-23}\text{ g}
    • C) 4.65×10−23 g4.65 \times 10^{-23}\text{ g}
    • D) 2.15×1022 g2.15 \times 10^{22}\text{ g}
  4. 4.

    A sample of pure argon gas contains 1.806×10241.806 \times 10^{24} atoms. How many moles of argon atoms are present in this sample?

    • A) 0.300 mol
    • B) 1.50 mol
    • C) 3.00 mol
    • D) 6.00 mol
  5. 5.

    How many individual oxygen atoms are contained in a 0.50 mol sample of gaseous carbon dioxide (CO2\text{CO}_2)?

    • A) 1.51×10231.51 \times 10^{23}
    • B) 3.01×10233.01 \times 10^{23}
    • C) 1.20×10241.20 \times 10^{24}
    • D) 6.02×10236.02 \times 10^{23}

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