Bonding in carbon compounds Knowledge-Based Practice

Chemistry · Organic Chemistry · Chemistry · Hydrocarbons

5 Chemistry practice questions on Bonding in carbon compounds. Questions that assess core concepts and understanding.

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Questions

  1. 1.

    How does an increase in the percentage of s-character in a carbon atom's hybrid orbital affect the carbon's effective electronegativity and the length of the resulting C−H\text{C}-\text{H} bond?

    • A) It decreases the carbon's electronegativity and increases the C−H\text{C}-\text{H} bond length.
    • B) It increases the carbon's electronegativity and decreases the C−H\text{C}-\text{H} bond length.
    • C) It decreases the carbon's electronegativity and decreases the C−H\text{C}-\text{H} bond length.
    • D) It increases the carbon's electronegativity and increases the C−H\text{C}-\text{H} bond length.
  2. 2.

    In a propadiene (CH2=C=CH2\text{CH}_2=\text{C}=\text{CH}_2) molecule, what is the hybridization of the central carbon atom and the relative geometric orientation of the two terminal CH2\text{CH}_2 planes?

    • A) The central carbon atom is sp2sp^2-hybridized, and the two terminal CH2\text{CH}_2 planes are coplanar.
    • B) The central carbon atom is spsp-hybridized, and the two terminal CH2\text{CH}_2 planes are mutually perpendicular.
    • C) The central carbon atom is spsp-hybridized, and the two terminal CH2\text{CH}_2 planes are coplanar.
    • D) The central carbon atom is sp3sp^3-hybridized, and the two terminal CH2\text{CH}_2 planes are oriented at an angle of 109.5∘109.5^\circ.
  3. 3.

    Which statement correctly compares the carbon–carbon bonds in ethane (C2H6\text{C}_2\text{H}_6), ethene (C2H4\text{C}_2\text{H}_4), and ethyne (C2H2\text{C}_2\text{H}_2)?

    • A) Ethane exhibits the shortest carbon–carbon bond length and the highest bond dissociation energy because single σ\sigma bonds provide the strongest axial orbital overlap.
    • B) Ethene has a shorter carbon–carbon bond length and higher bond dissociation energy than ethyne because sp2sp^2 hybrid orbitals have a greater percentage of s-character than spsp hybrid orbitals.
    • C) Ethyne exhibits the shortest carbon–carbon bond length and the highest bond dissociation energy because of its higher bond order and the greater s-character of its spsp hybrid orbitals.
    • D) Ethane has a shorter carbon–carbon bond length than ethene because the absence of π\pi electron repulsion allows the two carbon nuclei to approach each other more closely.
  4. 4.

    Which statement correctly describes the orbital overlaps that form the bonds in an ethene (C2H4\text{C}_2\text{H}_4) molecule?

    • A) One sp2–sp2sp^2\text{--}sp^2 σ\sigma bond and one p–pp\text{--}p π\pi bond between the carbon atoms, and sp2–ssp^2\text{--}s σ\sigma bonds between carbon and hydrogen atoms.
    • B) One sp3–sp3sp^3\text{--}sp^3 σ\sigma bond and one p–pp\text{--}p π\pi bond between the carbon atoms, and sp3–ssp^3\text{--}s σ\sigma bonds between carbon and hydrogen atoms.
    • C) Two sp2–sp2sp^2\text{--}sp^2 σ\sigma bonds between the carbon atoms, and p–sp\text{--}s σ\sigma bonds between carbon and hydrogen atoms.
    • D) One sp–spsp\text{--}sp σ\sigma bond and one p–pp\text{--}p π\pi bond between the carbon atoms, and sp–ssp\text{--}s σ\sigma bonds between carbon and hydrogen atoms.
  5. 5.

    Which option correctly gives the hybridization states of the carbon atoms from left to right and the total number of pi (π) bonds in a propyne molecule (CH₃–C≡CH)?

    • A) sp³, sp², sp and one π bond
    • B) sp³, sp, sp and two π bonds
    • C) sp², sp, sp and two π bonds
    • D) sp³, sp², sp² and one π bond

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