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Vector components

Physics • Math Tools for Physics • Transitional Reasoning • 8 questions

Vector components Transitional Reasoning Download PDF

Physics · Introduction to Physics · Physics · Math Tools for Physics

8 Physics practice questions on Vector components. Questions that build towards applied reasoning.

Questions

  1. 1.

    A marine research vessel monitors subsurface ocean currents on a Cartesian grid where the positive x-axis points east and the positive y-axis points north. The acoustic sensor records a current velocity vector v⃗\vec{v} with a magnitude of 25.0 cm/s flowing northwest, such that its northward component is 43\frac{4}{3} times the magnitude of its westward component (vy=43∣vx∣v_y = \frac{4}{3}|v_x|). What are the scalar components vxv_x and vyv_y of this velocity vector, and what is its expression in Cartesian unit-vector notation?

    • A) vx=15.0 cm/sv_x = 15.0\text{ cm/s}, vy=−20.0 cm/sv_y = -20.0\text{ cm/s}; v⃗=(15.0i^−20.0j^) cm/s\vec{v} = (15.0\hat{i} - 20.0\hat{j})\text{ cm/s}
    • B) vx=−20.0 cm/sv_x = -20.0\text{ cm/s}, vy=15.0 cm/sv_y = 15.0\text{ cm/s}; v⃗=(−20.0i^+15.0j^) cm/s\vec{v} = (-20.0\hat{i} + 15.0\hat{j})\text{ cm/s}
    • C) vx=−15.0 cm/sv_x = -15.0\text{ cm/s}, vy=−20.0 cm/sv_y = -20.0\text{ cm/s}; v⃗=(−15.0i^−20.0j^) cm/s\vec{v} = (-15.0\hat{i} - 20.0\hat{j})\text{ cm/s}
    • D) vx=−15.0 cm/sv_x = -15.0\text{ cm/s}, vy=20.0 cm/sv_y = 20.0\text{ cm/s}; v⃗=(−15.0i^+20.0j^) cm/s\vec{v} = (-15.0\hat{i} + 20.0\hat{j})\text{ cm/s}
  2. 2.

    A crate with a weight of 120 N rests on a ramp inclined at an angle of 30° above the horizontal. In physics, weight acts vertically downward and is resolved into two perpendicular components relative to the incline: one directed parallel to the ramp surface and one directed perpendicular to it. Given that sin⁡30∘=0.50\sin 30^\circ = 0.50 and cos⁡30∘=0.87\cos 30^\circ = 0.87, what are the magnitudes of the parallel component (W∥W_\parallel) and the perpendicular component (W⊥W_\perp)?

    • A) W∥=60 NW_\parallel = 60\text{ N} and W⊥=104.4 NW_\perp = 104.4\text{ N}
    • B) W∥=104.4 NW_\parallel = 104.4\text{ N} and W⊥=60 NW_\perp = 60\text{ N}
    • C) W∥=60 NW_\parallel = 60\text{ N} and W⊥=120 NW_\perp = 120\text{ N}
    • D) W∥=84.9 NW_\parallel = 84.9\text{ N} and W⊥=84.9 NW_\perp = 84.9\text{ N}
  3. 3.

    A rescue helicopter flies along a straight tracking path oriented 53∘53^\circ north of east. A radar monitoring station records that the eastward component of the helicopter's displacement is 18.0 km. Given that sin⁡53∘=0.80\sin 53^\circ = 0.80 and cos⁡53∘=0.60\cos 53^\circ = 0.60, what are the northward displacement component (dyd_y) and the total straight-line distance (dd) traveled by the helicopter?

    • A) dyd_y = 13.5 km, dd = 22.5 km
    • B) dyd_y = 14.4 km, dd = 18.0 km
    • C) dyd_y = 24.0 km, dd = 42.0 km
    • D) dyd_y = 24.0 km, dd = 30.0 km
  4. 4.

    An oceanographic sensor station monitors coastal currents on a Cartesian grid where the positive x-axis points east and the positive y-axis points north. The station records a localized current velocity with scalar components vx=−3.0 m/sv_x = -3.0\text{ m/s} and vy=3.03 m/sv_y = 3.0\sqrt{3}\text{ m/s}. What are the magnitude of this velocity vector and its standard direction angle measured counterclockwise from the positive x-axis?

    • A) 6.0 m/s and 120°
    • B) 6.0 m/s and 60°
    • C) 8.2 m/s and 120°
    • D) 8.2 m/s and 240°
  5. 5.

    An automated transport cart in a distribution center moves along a straight path from an initial position P1(16 m,3 m)P_1(16\text{ m}, 3\text{ m}) to a final position P2(4 m,12 m)P_2(4\text{ m}, 12\text{ m}) on a warehouse grid. What are the scalar components Δx\Delta x and Δy\Delta y of the cart's displacement vector, and what is the magnitude of this displacement?

    • A) Δx=−12 m\Delta x = -12\text{ m}, Δy=+9 m\Delta y = +9\text{ m}, and magnitude =15 m= 15\text{ m}
    • B) Δx=+12 m\Delta x = +12\text{ m}, Δy=−9 m\Delta y = -9\text{ m}, and magnitude =15 m= 15\text{ m}
    • C) Δx=+20 m\Delta x = +20\text{ m}, Δy=+15 m\Delta y = +15\text{ m}, and magnitude =25 m= 25\text{ m}
    • D) Δx=−12 m\Delta x = -12\text{ m}, Δy=+9 m\Delta y = +9\text{ m}, and magnitude =21 m= 21\text{ m}
  6. 6.

    An engineering team is testing the stability of an anchor ring subjected to two planar forces, A⃗\vec{A} and B⃗\vec{B}. Force A⃗\vec{A} has the known Cartesian components Ax=8.0 NA_x = 8.0\text{ N} and Ay=−3.0 NA_y = -3.0\text{ N}. To ensure safe alignment, the resultant force R⃗=A⃗+B⃗\vec{R} = \vec{A} + \vec{B} must act entirely in the positive y-direction with a magnitude of 7.0 N7.0\text{ N}. What must be the scalar components BxB_x and ByB_y of force B⃗\vec{B}?

    • A) Bx=8.0 NB_x = 8.0\text{ N} and By=4.0 NB_y = 4.0\text{ N}
    • B) Bx=−8.0 NB_x = -8.0\text{ N} and By=4.0 NB_y = 4.0\text{ N}
    • C) Bx=−8.0 NB_x = -8.0\text{ N} and By=10.0 NB_y = 10.0\text{ N}
    • D) Bx=8.0 NB_x = 8.0\text{ N} and By=10.0 NB_y = 10.0\text{ N}
  7. 7.

    An autonomous underwater vehicle detects an ocean current with a speed of 10 m/s directed at an angle of 60° below the negative x-axis in the third quadrant. To compensate for the drift, the vehicle navigation system must resolve this velocity vector into its Cartesian scalar components. Given that cos⁡60∘=0.50\cos 60^\circ = 0.50 and sin⁡60∘=0.87\sin 60^\circ = 0.87, what are the scalar components vxv_x and vyv_y of the current velocity?

    • A) vx=+5.0v_x = +5.0 m/s, vy=+8.7v_y = +8.7 m/s
    • B) vx=−8.7v_x = -8.7 m/s, vy=−5.0v_y = -5.0 m/s
    • C) vx=−5.0v_x = -5.0 m/s, vy=−8.7v_y = -8.7 m/s
    • D) vx=−5.0v_x = -5.0 m/s, vy=+8.7v_y = +8.7 m/s
  8. 8.

    During a laboratory investigation, a student pulls a test cart across a flat floor using a strap that exerts a tension force of 50 N directed upward and forward. The strap forms an angle of 37° with the vertical axis. Given that sin 37° = 0.60 and cos 37° = 0.80, what are the magnitudes of the horizontal component (FxF_x) and vertical component (FyF_y) of this tension force?

    • A) FxF_x = 30 N and FyF_y = 40 N
    • B) FxF_x = 40 N and FyF_y = 30 N
    • C) FxF_x = 50 N and FyF_y = 30 N
    • D) FxF_x = 40 N and FyF_y = 50 N