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Trigonometry for physics (right triangles, components)

Physics • Math Tools for Physics • Transitional Reasoning • 3 questions

Trigonometry for physics (right triangles, components) Transitional Reasoning Download PDF

Physics · Introduction to Physics · Physics · Math Tools for Physics

3 Physics practice questions on Trigonometry for physics (right triangles, components). Questions that build towards applied reasoning.

Questions

  1. 1.

    During an engineering test, a technician pushes a heavy crate up a ramp inclined at an angle α\alpha to the horizontal by applying a purely horizontal force of magnitude FF. To determine how this force influences motion along the incline, the technician resolves FF into components parallel (F∥F_{\parallel}) and perpendicular (F⊥F_{\perp}) to the ramp surface. Based on right-triangle trigonometry, which pair of expressions correctly represents the magnitudes of these two components?

    • A) F∥=Fsin⁡αF_{\parallel} = F \sin\alpha and F⊥=Fcos⁡αF_{\perp} = F \cos\alpha
    • B) F∥=Fcos⁡αF_{\parallel} = F \cos\alpha and F⊥=Fsin⁡αF_{\perp} = F \sin\alpha
    • C) F∥=Ftan⁡αF_{\parallel} = F \tan\alpha and F⊥=Fcos⁡αF_{\perp} = F \cos\alpha
    • D) F∥=Fcos⁡αF_{\parallel} = F \cos\alpha and F⊥=Ftan⁡αF_{\perp} = F \tan\alpha
  2. 2.

    An autonomous underwater glider travels along a straight path descending at an angle θ\theta below the horizontal surface of the sea. An onboard acoustic sensor records that the glider maintains a constant horizontal velocity component of magnitude vxv_x. Based on right-triangle trigonometry, which pair of expressions correctly represents the glider's total speed vv and its vertical descent speed vyv_y?

    • A) v=vxcos⁡θv = \frac{v_x}{\cos\theta} and vy=vxtan⁡θv_y = v_x \tan\theta
    • B) v=vxcos⁡θv = v_x \cos\theta and vy=vxsin⁡θv_y = v_x \sin\theta
    • C) v=vxsin⁡θv = \frac{v_x}{\sin\theta} and vy=vxtan⁡θv_y = \frac{v_x}{\tan\theta}
    • D) v=vxtan⁡θv = v_x \tan\theta and vy=vxcos⁡θv_y = \frac{v_x}{\cos\theta}
  3. 3.

    A rescue drone exerts a steady pulling force of magnitude TT on a tether attached to a ground crate. The tether is tilted such that it makes an angle θ\theta with the vertical axis. Which expressions correctly determine the horizontal component (TxT_x) and vertical component (TyT_y) of this force?

    • A) Tx=Tsin⁡θT_x = T \sin\theta and Ty=Tcos⁡θT_y = T \cos\theta
    • B) Tx=Tcos⁡θT_x = T \cos\theta and Ty=Tsin⁡θT_y = T \sin\theta
    • C) Tx=Ttan⁡θT_x = T \tan\theta and Ty=Tcos⁡θT_y = T \cos\theta
    • D) Tx=Tsin⁡θT_x = T \sin\theta and Ty=T/cos⁡θT_y = T / \cos\theta