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Integration by parts and partial fractions

Math • Calculus BC Topics • Knowledge-Based • 5 questions

Integration by parts and partial fractions Knowledge-Based Download PDF

Math · Calculus · Math · Calculus BC Topics

5 Math practice questions on Integration by parts and partial fractions. Questions that assess core concepts and understanding.

Questions

  1. 1.

    Evaluate the indefinite integral ∫e2xcos⁡x dx\int e^{2x} \cos x \, dx.

    • A) e2x5(2sin⁡x−cos⁡x)+C\frac{e^{2x}}{5}(2\sin x - \cos x) + C
    • B) e2x3(sin⁡x+2cos⁡x)+C\frac{e^{2x}}{3}(\sin x + 2\cos x) + C
    • C) e2x5(sin⁡x+2cos⁡x)+C\frac{e^{2x}}{5}(\sin x + 2\cos x) + C
    • D) e2x5(2cos⁡x−sin⁡x)+C\frac{e^{2x}}{5}(2\cos x - \sin x) + C
  2. 2.

    Evaluate the indefinite integral ∫x3−2xx2+3x+2 dx\int \frac{x^3 - 2x}{x^2 + 3x + 2} \, dx for x>0x > 0.

    • A) 12x2+3x+ln⁡(x+1)+4ln⁡(x+2)+C\frac{1}{2}x^2 + 3x + \ln(x+1) + 4\ln(x+2) + C
    • B) 12x2−3x+4ln⁡(x+1)+ln⁡(x+2)+C\frac{1}{2}x^2 - 3x + 4\ln(x+1) + \ln(x+2) + C
    • C) 12x2−3x+ln⁡(x+1)+4ln⁡(x+2)+C\frac{1}{2}x^2 - 3x + \ln(x+1) + 4\ln(x+2) + C
    • D) x2−3x+2ln⁡(x+1)+3ln⁡(x+2)+Cx^2 - 3x + 2\ln(x+1) + 3\ln(x+2) + C
  3. 3.

    Evaluate the indefinite integral ∫arctan⁡xx2 dx\int \frac{\arctan x}{x^2} \, dx for x>0x > 0.

    • A) −arctan⁡xx−ln⁡x+12ln⁡(x2+1)+C-\frac{\arctan x}{x} - \ln x + \frac{1}{2} \ln(x^2 + 1) + C
    • B) arctan⁡xx+ln⁡x−12ln⁡(x2+1)+C\frac{\arctan x}{x} + \ln x - \frac{1}{2} \ln(x^2 + 1) + C
    • C) −arctan⁡xx+ln⁡x−ln⁡(x2+1)+C-\frac{\arctan x}{x} + \ln x - \ln(x^2 + 1) + C
    • D) −arctan⁡xx+ln⁡x−12ln⁡(x2+1)+C-\frac{\arctan x}{x} + \ln x - \frac{1}{2} \ln(x^2 + 1) + C
  4. 4.

    Which of the following is equivalent to the indefinite integral ∫ln⁡(x2−1) dx\int \ln(x^2 - 1) \, dx for x>1x > 1?

    • A) (x−1)ln⁡(x−1)+(x+1)ln⁡(x+1)−2x+C(x - 1)\ln(x - 1) + (x + 1)\ln(x + 1) - 2x + C
    • B) (x+1)ln⁡(x−1)+(x−1)ln⁡(x+1)−2x+C(x + 1)\ln(x - 1) + (x - 1)\ln(x + 1) - 2x + C
    • C) (x−1)ln⁡(x−1)−(x+1)ln⁡(x+1)+2x+C(x - 1)\ln(x - 1) - (x + 1)\ln(x + 1) + 2x + C
    • D) xln⁡(x2−1)−x+Cx\ln(x^2 - 1) - x + C
  5. 5.

    Evaluate the indefinite integral ∫ln⁡x(x+1)2 dx\int \frac{\ln x}{(x+1)^2} \, dx for x>0x > 0.

    • A) ln⁡xx+1+ln⁡x−ln⁡(x+1)+C\frac{\ln x}{x+1} + \ln x - \ln(x+1) + C
    • B) −ln⁡xx+1+ln⁡x+ln⁡(x+1)+C-\frac{\ln x}{x+1} + \ln x + \ln(x+1) + C
    • C) −ln⁡x(x+1)2+ln⁡x−ln⁡(x+1)+C-\frac{\ln x}{(x+1)^2} + \ln x - \ln(x+1) + C
    • D) −ln⁡xx+1+ln⁡x−ln⁡(x+1)+C-\frac{\ln x}{x+1} + \ln x - \ln(x+1) + C