Infinite series Knowledge-Based Study

Math · Calculus · Math · Calculus BC Topics

Math topic explanations on Infinite series.

Study notes

  1. What is an Infinite Series?

    An infinite series is the formal sum of an infinite sequence of terms: ∑n=1∞an=a1+a2+a3+⋯\sum_{n=1}^{\infty} a_n = a_1 + a_2 + a_3 + \cdots

    Sequence of Partial Sums

    To evaluate whether an infinite series adds up to a finite real number, we define the n-th partial sum, denoted by SnS_n:

    Sn=∑k=1nak=a1+a2+⋯+anS_n = \sum_{k=1}^{n} a_k = a_1 + a_2 + \cdots + a_n

    We say that the series ∑n=1∞an\sum_{n=1}^{\infty} a_n converges to the sum SS if the sequence of partial sums {Sn}\{S_n\} has a finite limit as n→∞n\to\infty:

    lim⁡n→∞Sn=S\lim_{n \to \infty} S_n = S

    If lim⁡n→∞Sn\lim_{n \to \infty} S_n does not exist or equals ±∞\pm\infty, the series diverges.

    The Divergence Test (n-th Term Test)

    If ∑n=1∞an\sum_{n=1}^{\infty} a_n converges, then lim⁡n→∞an=0\lim_{n \to \infty} a_n = 0. Consequently, its contrapositive provides a practical preliminary test:

    Divergence Test: If lim⁡n→∞an≠0\lim_{n \to \infty} a_n \neq 0 or does not exist, then the series ∑n=1∞an\sum_{n=1}^{\infty} a_n diverges.

    Caution: If lim⁡n→∞an=0\lim_{n \to \infty} a_n = 0, the test is inconclusive. For example, the harmonic series ∑n=1∞1n\sum_{n=1}^{\infty} \frac{1}{n} diverges even though lim⁡n→∞1n=0\lim_{n \to \infty} \frac{1}{n} = 0.

    Geometric Series

    A geometric series has the form: ∑n=0∞arn=a+ar+ar2+⋯\sum_{n=0}^{\infty} a r^n = a + ar + ar^2 + \cdots

    • If ∣r∣<1|r| < 1, the series converges to S=a1−rS = \frac{a}{1 - r}, where aa is the first term and rr is the common ratio.
    • If ∣r∣≥1|r| \ge 1, the series diverges.

    The Integral Test and p-Series

    Suppose f(x)f(x) is a continuous, positive, and decreasing function on [1,∞)[1, \infty) such that f(n)=anf(n) = a_n. Then ∑n=1∞an\sum_{n=1}^{\infty} a_n and ∫1∞f(x) dx\int_{1}^{\infty} f(x)\,dx either both converge or both diverge.

    Applying the Integral Test to f(x)=1xpf(x) = \frac{1}{x^p} yields the p-Series Test: ∑n=1∞1np\sum_{n=1}^{\infty} \frac{1}{n^p}

    • Converges if p>1p > 1.
    • Diverges if p≤1p \le 1.

    Direct and Limit Comparison Tests

    For series with positive terms an>0a_n > 0 and bn>0b_n > 0:

    • Direct Comparison Test: If an≤bna_n \le b_n for all large nn, and ∑bn\sum b_n converges, then ∑an\sum a_n converges. If an≥bna_n \ge b_n and ∑bn\sum b_n diverges, then ∑an\sum a_n diverges.
    • Limit Comparison Test: If lim⁡n→∞anbn=L\lim_{n \to \infty} \frac{a_n}{b_n} = L where 0<L<∞0 < L < \infty, then ∑an\sum a_n and ∑bn\sum b_n either both converge or both diverge.

    Alternating Series Test (Leibniz's Test)

    An alternating series has the form ∑n=1∞(−1)n−1bn\sum_{n=1}^{\infty} (-1)^{n-1} b_n with bn>0b_n > 0. The series converges if both conditions hold:

    1. bn+1≤bnb_{n+1} \le b_n for all nn (the terms are non-increasing).
    2. lim⁡n→∞bn=0\lim_{n \to \infty} b_n = 0.

    Alternating Series Estimation Theorem

    If an alternating series satisfies the test and sums to SS, the error in approximating SS with the nn-th partial sum SnS_n satisfies: ∣Rn∣=∣S−Sn∣≤bn+1|R_n| = |S - S_n| \le b_{n+1}

    Absolute vs. Conditional Convergence

    • A series ∑an\sum a_n is absolutely convergent if ∑∣an∣\sum |a_n| converges. Absolute convergence implies ordinary convergence.
    • A series is conditionally convergent if ∑an\sum a_n converges, but ∑∣an∣\sum |a_n| diverges (e.g., the alternating harmonic series ∑n=1∞(−1)n−1n\sum_{n=1}^{\infty} \frac{(-1)^{n-1}}{n}).

    The Ratio Test

    Let L=lim⁡n→∞∣an+1an∣L = \lim_{n \to \infty} \left| \frac{a_{n+1}}{a_n} \right|.

    • If L<1L < 1, the series ∑an\sum a_n is absolutely convergent.
    • If L>1L > 1 or L=∞L = \infty, the series diverges.
    • If L=1L = 1, the test is inconclusive (use another test such as Comparison or Integral Test).

    The Ratio Test is particularly effective for series involving factorials (e.g., n!n!) or exponential expressions (e.g., 2n2^n).

    The Root Test

    Let L=lim⁡n→∞∣an∣nL = \lim_{n \to \infty} \sqrt[n]{|a_n|}.

    • If L<1L < 1, the series converges absolutely.
    • If L>1L > 1 or L=∞L = \infty, the series diverges.
    • If L=1L = 1, the test is inconclusive.

    The Root Test is useful when terms involve expressions raised to the nn-th power, such as (an)n(a_n)^n.