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Bonding in carbon compounds

Chemistry • Hydrocarbons • Knowledge-Based • 5 questions

Bonding in carbon compounds Knowledge-Based Download PDF

Chemistry · Organic Chemistry · Chemistry · Hydrocarbons

5 Chemistry practice questions on Bonding in carbon compounds. Questions that assess core concepts and understanding.

Questions

  1. 1.

    Which of the following statements correctly describes the orbital overlaps that form the carbon–carbon triple bond in an ethyne (C2H2\text{C}_2\text{H}_2) molecule?

    • A) One π\pi bond formed by the coaxial overlap of spsp hybrid orbitals and two σ\sigma bonds formed by the sideways overlap of unhybridized 2p2p orbitals
    • B) Three σ\sigma bonds formed by the head-on overlap of three equivalent sp2sp^2 hybrid orbitals from each carbon atom
    • C) Two σ\sigma bonds formed by the head-on overlap of spsp hybrid orbitals and one π\pi bond formed by the sideways overlap of unhybridized 2p2p orbitals
    • D) One σ\sigma bond formed by the head-on overlap of spsp hybrid orbitals and two π\pi bonds formed by the sideways overlap of unhybridized 2p2p orbitals
  2. 2.

    Which of the following statements correctly explains how the four equivalent carbon–hydrogen (C−H\text{C}-\text{H}) bonds in a methane (CH4\text{CH}_4) molecule are formed according to valence bond theory?

    • A) Carbon uses its unhybridized 2s2s and three 2p2p valence orbitals directly to overlap with hydrogen 1s1s orbitals, forming bonds with different lengths and energies.
    • B) One 2s2s and three 2p2p orbitals of carbon mix to form four equivalent sp3sp^3 hybrid orbitals, each overlapping head-on with a hydrogen 1s1s orbital in a tetrahedral geometry.
    • C) Carbon undergoes sp2sp^2 hybridization to establish three coplanar σ\sigma bonds, while the remaining unhybridized 2p2p orbital forms a delocalized bond with the fourth hydrogen atom.
    • D) An electron is promoted from the 2s2s subshell into a 3d3d orbital to generate four sp2dsp^2d hybrid orbitals directed toward the corners of a square planar structure.
  3. 3.

    Which of the following statements correctly explains why rotation about the carbon–carbon double bond in alkenes is restricted at ordinary temperatures, unlike rotation about the carbon–carbon single bond in alkanes?

    • A) The two carbon atoms are held together by two collinear σ\sigma bonds that cannot twist without altering their ideal bond angles.
    • B) The higher electronegativity of sp2sp^2-hybridized carbon atoms generates an electrostatic barrier that locks the atoms in place.
    • C) Strong steric hindrance between valence shell nonbonding electron pairs on the two carbon atoms prevents torsional motion.
    • D) Rotating around the carbon–carbon axis would disrupt the parallel, sideways overlap of the unhybridized 2p2p orbitals that form the π\pi bond.
  4. 4.

    Which of the following statements correctly compares the carbon–carbon bond length and bond strength among ethane (C2H6\text{C}_2\text{H}_6), ethene (C2H4\text{C}_2\text{H}_4), and ethyne (C2H2\text{C}_2\text{H}_2)?

    • A) Ethyne has the shortest carbon–carbon bond length and the highest carbon–carbon bond strength among the three molecules.
    • B) Ethane has the shortest carbon–carbon bond length and the highest carbon–carbon bond strength among the three molecules.
    • C) Ethyne has the longest carbon–carbon bond length and the lowest carbon–carbon bond strength among the three molecules.
    • D) Ethane has the longest carbon–carbon bond length and the highest carbon–carbon bond strength among the three molecules.
  5. 5.

    Which of the following correctly identifies the hybridization of each carbon atom and the total number of σ\sigma (sigma) and π\pi (pi) bonds in an ethene (C2H4\text{C}_2\text{H}_4) molecule?

    • A) sp3sp^3 hybridized, with 4 σ\sigma bonds and 2 π\pi bonds
    • B) sp3sp^3 hybridized, with 5 σ\sigma bonds and 1 π\pi bond
    • C) sp2sp^2 hybridized, with 4 σ\sigma bonds and 2 π\pi bonds
    • D) sp2sp^2 hybridized, with 5 σ\sigma bonds and 1 π\pi bond