PDF Downloads

Scientific notation

Chemistry • Measurement & Units • Transitional Reasoning • 10 questions

Scientific notation Transitional Reasoning Download PDF

Chemistry · Introduction to Chemistry · Chemistry · Measurement & Units

10 Chemistry practice questions on Scientific notation. Questions that build towards applied reasoning.

Questions

  1. 1.

    During a time-of-flight mass spectrometry demonstration, an ionized molecule travels through a drift tube with a length of 1.20 meters at a constant speed of 4.00×105 m/s4.00 \times 10^5\text{ m/s}. To set the detection window, a chemistry student must determine the time required, in seconds, for the ion to reach the detector. What is this flight time in seconds, expressed in standard scientific notation (N×10nN \times 10^n, where 1≤N<101 \le N < 10)?

    • A) 3.00×10−4 s3.00 \times 10^{-4}\text{ s}
    • B) 3.00×10−5 s3.00 \times 10^{-5}\text{ s}
    • C) 0.300×10−5 s0.300 \times 10^{-5}\text{ s}
    • D) 3.00×10−6 s3.00 \times 10^{-6}\text{ s}
  2. 2.

    A chemistry student determines the thickness of a rectangular sheet of aluminum foil using laboratory measurements. The sheet has a length of 3.0×1013.0 \times 10^1 cm, a width of 2.0×1012.0 \times 10^1 cm, and a mass of 3.24 g. Given that the density of aluminum is 2.70 g/cm³, what is the thickness of the foil in centimeters, expressed in standard scientific notation (N×10nN \times 10^n, where 1≤N<101 \le N < 10)?

    • A) 2.0×10−32.0 \times 10^{-3} cm
    • B) 2.0×10−22.0 \times 10^{-2} cm
    • C) 5.0×10−35.0 \times 10^{-3} cm
    • D) 2.0×10−42.0 \times 10^{-4} cm
  3. 3.

    To understand atomic scale in an introductory chemistry unit, a student compares the dimensions of a gold atom to its nucleus. The diameter of the gold atom is measured as 1.0×10−10 m1.0 \times 10^{-10}\text{ m}, while the diameter of its nucleus is 2.0×10−15 m2.0 \times 10^{-15}\text{ m}. How many times larger is the diameter of the atom than the diameter of the nucleus, expressed in standard scientific notation (N×10nN \times 10^n, where 1≤N<101 \le N < 10)?

    • A) 2.0×1042.0 \times 10^4
    • B) 5.0×1045.0 \times 10^4
    • C) 5.0×1055.0 \times 10^5
    • D) 5.0×1065.0 \times 10^6
  4. 4.

    During a laboratory investigation of volatile liquids, a student records the total pressure inside a sealed flask as 1.04×105 Pa1.04 \times 10^5\text{ Pa}. After selectively condensing the vapor, the remaining non-condensable gas exerts a pressure of 9.6×104 Pa9.6 \times 10^4\text{ Pa}. What is the partial pressure of the condensed vapor in pascals, expressed in standard scientific notation (N×10nN \times 10^n, where 1≤N<101 \le N < 10)?

    • A) 8.0×103 Pa8.0 \times 10^3\text{ Pa}
    • B) 8.0×104 Pa8.0 \times 10^4\text{ Pa}
    • C) 8.56×104 Pa8.56 \times 10^4\text{ Pa}
    • D) 8.0×102 Pa8.0 \times 10^2\text{ Pa}
  5. 5.

    An environmental chemist monitors airborne particulate matter by operating an air-sampling pump at a constant volumetric flow rate of 1.5×10−2 m3/min1.5 \times 10^{-2}\text{ m}^3\text{/min} for 8.0×102 min8.0 \times 10^2\text{ min}. Over this period, the collection filter traps a total particulate mass of 7.2×10−4 g7.2 \times 10^{-4}\text{ g}. What is the concentration of airborne particulates in grams per cubic meter (g/m3\text{g/m}^3), expressed in standard scientific notation (N×10nN \times 10^n, where 1≤N<101 \le N < 10)?

    • A) 6.0×10−3 g/m36.0 \times 10^{-3}\text{ g/m}^3
    • B) 6.0×10−4 g/m36.0 \times 10^{-4}\text{ g/m}^3
    • C) 6.0×10−6 g/m36.0 \times 10^{-6}\text{ g/m}^3
    • D) 6.0×10−5 g/m36.0 \times 10^{-5}\text{ g/m}^3
  6. 6.

    During an experiment measuring evaporation rates in an introductory chemistry laboratory, a student monitors a liquid solvent placed on an electronic balance. Over a measured time interval of 4.5×102 s4.5 \times 10^2\text{ s}, the solvent mass decreases from 8.6×10−1 g8.6 \times 10^{-1}\text{ g} to 5.0×10−1 g5.0 \times 10^{-1}\text{ g}. What is the average rate of mass loss in grams per second (g/s\text{g/s}), expressed in standard scientific notation (N×10nN \times 10^n, where 1≤N<101 \le N < 10)?

    • A) 8.0×10−2 g/s8.0 \times 10^{-2}\text{ g/s}
    • B) 8.0×10−3 g/s8.0 \times 10^{-3}\text{ g/s}
    • C) 8.0×10−4 g/s8.0 \times 10^{-4}\text{ g/s}
    • D) 8.0×10−5 g/s8.0 \times 10^{-5}\text{ g/s}
  7. 7.

    During an investigation of nanomaterials, a materials chemist synthesizes uniform cubic nanocrystals of titanium dioxide. Each nanocrystal has an edge length of 3.0×10−8 m3.0 \times 10^{-8}\text{ m}. To model surface interactions, the chemist must determine the volume of a single nanocrystal expressed in standard scientific notation N×10nN \times 10^n, where 1≤N<101 \le N < 10. What is the volume of one nanocrystal in cubic meters (m3\text{m}^3)?

    • A) 9.0×10−24 m39.0 \times 10^{-24}\text{ m}^3
    • B) 2.7×10−25 m32.7 \times 10^{-25}\text{ m}^3
    • C) 2.7×10−23 m32.7 \times 10^{-23}\text{ m}^3
    • D) 2.7×10−24 m32.7 \times 10^{-24}\text{ m}^3
  8. 8.

    In an environmental water quality test, an analyst collects suspended particulate matter from two distinct runoff samples. The first filter traps 3.15×10−2 g3.15 \times 10^{-2}\text{ g} of solid residue, while the second filter traps 4.5×10−3 g4.5 \times 10^{-3}\text{ g} of solid residue. To document the total particulate yield, the analyst must sum these two quantities and report the result in proper scientific notation N×10nN \times 10^n, where 1≤N<101 \le N < 10. What is the total mass of the collected residue in grams?

    • A) 3.60×10−2 g3.60 \times 10^{-2}\text{ g}
    • B) 7.65×10−2 g7.65 \times 10^{-2}\text{ g}
    • C) 3.60×10−3 g3.60 \times 10^{-3}\text{ g}
    • D) 7.65×10−5 g7.65 \times 10^{-5}\text{ g}
  9. 9.

    A chemist measures a 0.0480 g sample of a synthesized catalyst containing 1.2×10191.2 \times 10^{19} identical micro-crystals. To assess particle uniformity, the chemist needs to determine the average mass of a single micro-crystal by dividing the total sample mass by the crystal count. What is the average mass of one micro-crystal expressed in grams in standard scientific notation?

    • A) 4.0×10−17 g4.0 \times 10^{-17}\text{ g}
    • B) 4.0×10−20 g4.0 \times 10^{-20}\text{ g}
    • C) 4.0×10−21 g4.0 \times 10^{-21}\text{ g}
    • D) 4.0×10−22 g4.0 \times 10^{-22}\text{ g}
  10. 10.

    In an analytical chemistry procedure, a technician measures a 0.0025 L aliquot of a solution containing a dissolved dye at a concentration of 6.0×10−46.0 \times 10^{-4} g/L. To calculate the total mass of the dye present, the volume and concentration must be multiplied and the result expressed in standard scientific notation N×10nN \times 10^n, where 1≤N<101 \le N < 10. What is the total mass of the dye in grams?

    • A) 1.5×10−61.5 \times 10^{-6} g
    • B) 1.5×10−71.5 \times 10^{-7} g
    • C) 15×10−715 \times 10^{-7} g
    • D) 1.5×10−81.5 \times 10^{-8} g