Collisions in two dimensions Knowledge-Based Study

Physics · Momentum · Physics · Conservation of Momentum & Collisions

Physics topic explanations on Collisions in two dimensions.

Study notes

  1. Momentum as a Vector Quantity

    In one-dimensional mechanics, momentum is often treated with simple positive and negative signs to indicate direction. However, when objects collide at angles or deflect away from their original lines of motion, we must treat momentum strictly as a two-dimensional vector quantity.

    Linear momentum is defined as:

    p⃗=mv⃗\vec{p} = m\vec{v}

    Because velocity is a vector, momentum always points in the exact same direction as the velocity vector. In a two-dimensional Cartesian coordinate system, any momentum vector p⃗\vec{p} can be resolved into perpendicular components along the x-axis and y-axis:

    • x-component: px=mvx=mvcos⁡θp_x = m v_x = m v \cos\theta
    • y-component: py=mvy=mvsin⁡θp_y = m v_y = m v \sin\theta

    Here, θ\theta is measured relative to the reference coordinate axes. Analyzing collisions in two dimensions relies fundamentally on treating these perpendicular directions independently.

    Component-Wise Conservation Laws

    According to Newton's third law of motion, the internal interaction forces between colliding objects are equal in magnitude and opposite in direction. In an isolated system where external forces such as friction and gravity are negligible or balance out, the total momentum vector remains constant:

    p⃗total, initial=p⃗total, final\vec{p}_{\text{total, initial}} = \vec{p}_{\text{total, final}}

    Because two perpendicular directions do not exert forces on one another, the conservation of linear momentum holds true separately along each coordinate axis:

    • Conservation along the x-axis: ∑pix=∑pfx\sum p_{ix} = \sum p_{fx} m1v1ix+m2v2ix=m1v1fx+m2v2fxm_1 v_{1ix} + m_2 v_{2ix} = m_1 v_{1fx} + m_2 v_{2fx}
    • Conservation along the y-axis: ∑piy=∑pfy\sum p_{iy} = \sum p_{fy} m1v1iy+m2v2iy=m1v1fy+m2v2fym_1 v_{1iy} + m_2 v_{2iy} = m_1 v_{1fy} + m_2 v_{2fy}

    These two independent scalar equations allow us to solve for up to two unknown quantities, such as an unknown final speed and a scattering angle, or two unknown component velocities.

    Energy Considerations and Collision Types

    While total linear momentum is conserved in all isolated collisions, mechanical energy is not necessarily conserved. Collisions in two dimensions are categorized based on what happens to the total kinetic energy KK of the system:

    • Elastic Collisions: Total kinetic energy is strictly conserved: ∑Ki=∑Kf\sum K_i = \sum K_f 12m1v1i2+12m2v2i2=12m1v1f2+12m2v2f2\frac{1}{2}m_1 v_{1i}^2 + \frac{1}{2}m_2 v_{2i}^2 = \frac{1}{2}m_1 v_{1f}^2 + \frac{1}{2}m_2 v_{2f}^2 For an elastic glancing collision between two identical masses where one mass is initially stationary, the trajectories of the two particles after the collision are perpendicular to each other, meaning their separation angle is 90 degrees.
    • Inelastic Collisions: Some initial kinetic energy is transformed into thermal energy, sound, or permanent deformation: ∑Ki>∑Kf\sum K_i > \sum K_f
    • Completely Inelastic Collisions: The colliding bodies stick together after impact and move with a single common final velocity v⃗f\vec{v}_f: m1v⃗1i+m2v⃗2i=(m1+m2)v⃗fm_1 \vec{v}_{1i} + m_2 \vec{v}_{2i} = (m_1 + m_2)\vec{v}_f

    Systematic Approach to 2D Collisions

    To successfully analyze two-dimensional collision problems, follow these systematic steps:

    1. Establish a Coordinate System: Align the x-axis with the initial motion of one of the particles whenever possible to simplify components (often making one initial y-velocity zero).
    2. Resolve Initial Velocities: Write down the mass, initial velocity magnitude, and direction angles for each object. Calculate pixp_{ix} and piyp_{iy} for the whole system.
    3. Express Final Momentum Components: Use trigonometric functions (cos⁡θ\cos\theta and sin⁡θ\sin\theta) to express the unknown final momentum components in terms of unknown speeds or angles. Pay close attention to signs: velocities pointing downward or to the left require negative values.
    4. Set Up and Solve Equations: Set total initial momentum equal to total final momentum along the x-axis and y-axis independently. Solve the resulting system of algebraic equations for the unknown values.
    5. Verify Results: Check whether vector magnitudes are positive and verify that the kinetic energy condition matches the stated collision type.