A 10 kg steel plate rests on a horizontal laboratory workbench while a mechanical clamp exerts a constant downward force of 20 N on its upper surface. An overhead cable attached to the plate pulls vertically upward with a tension of 30 N without lifting the plate. Taking $g = 10\text{ m/s}^2$, what is the initial magnitude of the normal force exerted by the workbench on the plate, and what does this normal force become if the cable tension is increased to 130 N?

A) 110 N; it decreases to -10 N because the upward tension exceeds the combined downward forces.

B) 150 N; it decreases to 10 N because the upward cable tension partially balances the weight.

C) 90 N; it decreases to 0 N because the plate loses contact with the workbench.

D) 70 N; it remains unchanged at 70 N because the normal force depends only on the mass of the plate.

A sealed cargo crate with a mass of 40 kg rests on the flat, horizontal bed of a transport truck moving along a level straight highway. As the truck speeds up, it accelerates forward at a constant rate of $3.0\text{ m/s}^2$ while the crate remains stationary relative to the truck bed without slipping or tipping. Taking $g = 10\text{ m/s}^2$, what is the magnitude of the normal force exerted by the truck bed on the crate during this acceleration, and how does it compare to the normal force when the truck was at rest?

A) 520 N, which is greater than when at rest because the forward acceleration adds directly to the downward gravitational load.

B) 400 N, which is equal to when at rest because the crate has zero vertical acceleration and normal force balances vertical forces.

C) 418 N, which is greater than when at rest because the normal force represents the combined vector sum of horizontal and vertical contact forces.

D) 280 N, which is less than when at rest because forward motion partially relieves the downward perpendicular pressure on the surface.

In an automotive wind tunnel test, a 5.0 kg aerodynamic vehicle model rests stationary on a flat, horizontal surface equipped with force sensors. When the wind tunnel is activated, air flowing over the vehicle produces a constant downward aerodynamic downforce of 25 N along with a horizontal drag force of 10 N. Taking $g = 10\text{ m/s}^2$, what is the total normal force exerted by the surface on the vehicle, and why does this force change when the wind tunnel is operating?

A) 50 N; the normal force is an intrinsic reaction force that always equals the object's gravitational weight regardless of applied aerodynamic loads.

B) 25 N; the normal force decreases because high-speed airflow over the vehicle generates lift that reduces the contact load on the surface.

C) 85 N; the normal force must scale up to balance the scalar sum of the vehicle's weight, the downforce, and the horizontal drag force.

D) 75 N; the normal force acts perpendicular to the surface and increases to balance the sum of the gravitational weight and the downward aerodynamic force, maintaining vertical equilibrium.

An interior painter uses an extension pole to hold a 3.0 kg flat drywall patch stationary against a horizontal ceiling by applying a constant upward vertical force of 45 N. Assuming the patch is in static equilibrium and taking $g = 10\text{ m/s}^2$, what are the magnitude and direction of the normal force exerted by the ceiling on the drywall patch?

A) 15 N, directed vertically upward

B) 15 N, directed vertically downward

C) 30 N, directed vertically upward

D) 75 N, directed vertically downward

A laboratory technician pushes two contacting rectangular blocks, Block X of mass 2.0 kg and Block Y of mass 3.0 kg, across a frictionless horizontal bench by applying a constant horizontal force of 25 N directly to Block X. Assuming the blocks remain in contact and taking $g = 10\text{ m/s}^2$, what are the magnitudes of the horizontal normal force exerted by Block X on Block Y and the vertical normal force exerted by the bench on Block Y?

A) Horizontal normal force = 25 N; vertical normal force = 50 N

B) Horizontal normal force = 10 N; vertical normal force = 30 N

C) Horizontal normal force = 25 N; vertical normal force = 30 N

D) Horizontal normal force = 15 N; vertical normal force = 30 N

A student investigates how surface orientation influences contact forces by placing a 6.0 kg wooden block at rest on an adjustable inclined ramp. The inclination angle of the ramp relative to the horizontal is initially 0° and is gradually tilted up to 60°. Taking $g = 10\text{ m/s}^2$ and $\cos 60^\circ = 0.50$, what is the magnitude of the normal force exerted by the ramp on the block at 60°, and why does this normal force decrease as the incline angle increases?

A) 60 N, because the normal force must always balance the total gravitational force acting on the object.

B) 52 N, because the ramp must counteract both the gravitational force and impending sliding motion.

C) 30 N, because the component of gravity perpendicular to the ramp surface decreases as the tilt angle increases.

D) 30 N, because static friction gradually replaces the normal force as the incline becomes steeper.

A 50 kg student stands on a calibrated scale on the floor of an elevator that is descending toward the ground level. As it approaches its destination, the elevator slows down at a constant rate of $2.0\text{ m/s}^2$. Taking $g = 10\text{ m/s}^2$, what is the magnitude of the normal force exerted by the scale on the student, and how does this force compare to the gravitational force acting on the student?

A) 500 N; it is equal to the gravitational force because the normal force and gravitational force always form an action-reaction pair on horizontal surfaces.

B) 400 N; it is less than the gravitational force because downward motion always reduces the contact force between a surface and an object.

C) 100 N; it is less than the gravitational force because the scale only needs to exert the force required to produce the acceleration.

D) 600 N; it is greater than the gravitational force because an upward net force is required to decelerate the downward motion.

A student presses a 0.5 kg eraser against a flat vertical whiteboard by applying a horizontal pushing force of 15 N directly toward the board, holding the eraser at rest. Which statement correctly identifies the magnitude and direction of the normal force exerted by the whiteboard on the eraser, and describes how this normal force changes if the horizontal push is increased to 25 N while the eraser remains stationary? (Take $g = 10\text{ m/s}^2$.)

A) The normal force is 15 N directed horizontally away from the board, and it increases to 25 N when the push is increased.

B) The normal force is 5 N directed vertically upward, and it remains 5 N because the eraser's mass is unchanged.

C) The normal force is 15 N directed horizontally away from the board, but it remains constant at 15 N because normal force depends solely on the object's weight.

D) The normal force is 20 N directed perpendicularly outward, and it increases to 30 N by combining the push with the gravitational force.

A warehouse worker pulls a cargo crate of mass 20 kg across a horizontal concrete floor by exerting a tension force of 50 N through a strap inclined at an angle of 37° above the horizontal. The crate slides forward along the floor without lifting off the ground (take $g = 10\text{ m/s}^2$, $\sin 37^\circ = 0.60$, and $\cos 37^\circ = 0.80$). What is the magnitude of the normal force exerted by the floor on the crate, and how does it compare to the crate's weight?

A) 200 N, because the normal force on a horizontal surface must always equal the object's gravitational weight.

B) 230 N, because the applied pulling force presses the crate harder against the ground by adding its vertical component.

C) 160 N, because the horizontal component of the tension reduces the contact force exerted by the floor.

D) 170 N, because the upward vertical component of the tension partially supports the crate's weight.

Normal force Transitional Reasoning Practice

Physics · Forces & Newton's Laws · Physics · Applications of Newton's Laws

10 Physics practice questions on Normal force. Questions that build towards applied reasoning.

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Questions

1.
A package with a mass of 12 kg is held stationary on a smooth, frictionless ramp inclined at an angle of 37° above the horizontal by a constant horizontal pushing force. Taking $g = 10\text{ m/s}^2$ , $\sin 37^\circ = 0.60$ , and $\cos 37^\circ = 0.80$ , what is the magnitude of the normal force exerted by the ramp on the package?
- A) 150 N
- B) 120 N
- C) 96 N
- D) 72 N
2.
A 10 kg steel plate rests on a horizontal laboratory workbench while a mechanical clamp exerts a constant downward force of 20 N on its upper surface. An overhead cable attached to the plate pulls vertically upward with a tension of 30 N without lifting the plate. Taking $g = 10\text{ m/s}^2$ , what is the initial magnitude of the normal force exerted by the workbench on the plate, and what does this normal force become if the cable tension is increased to 130 N?
- A) 110 N; it decreases to -10 N because the upward tension exceeds the combined downward forces.
- B) 150 N; it decreases to 10 N because the upward cable tension partially balances the weight.
- C) 90 N; it decreases to 0 N because the plate loses contact with the workbench.
- D) 70 N; it remains unchanged at 70 N because the normal force depends only on the mass of the plate.
3.
A sealed cargo crate with a mass of 40 kg rests on the flat, horizontal bed of a transport truck moving along a level straight highway. As the truck speeds up, it accelerates forward at a constant rate of $3.0\text{ m/s}^2$ while the crate remains stationary relative to the truck bed without slipping or tipping. Taking $g = 10\text{ m/s}^2$ , what is the magnitude of the normal force exerted by the truck bed on the crate during this acceleration, and how does it compare to the normal force when the truck was at rest?
- A) 520 N, which is greater than when at rest because the forward acceleration adds directly to the downward gravitational load.
- B) 400 N, which is equal to when at rest because the crate has zero vertical acceleration and normal force balances vertical forces.
- C) 418 N, which is greater than when at rest because the normal force represents the combined vector sum of horizontal and vertical contact forces.
- D) 280 N, which is less than when at rest because forward motion partially relieves the downward perpendicular pressure on the surface.
4.
In an automotive wind tunnel test, a 5.0 kg aerodynamic vehicle model rests stationary on a flat, horizontal surface equipped with force sensors. When the wind tunnel is activated, air flowing over the vehicle produces a constant downward aerodynamic downforce of 25 N along with a horizontal drag force of 10 N. Taking $g = 10\text{ m/s}^2$ , what is the total normal force exerted by the surface on the vehicle, and why does this force change when the wind tunnel is operating?
- A) 50 N; the normal force is an intrinsic reaction force that always equals the object's gravitational weight regardless of applied aerodynamic loads.
- B) 25 N; the normal force decreases because high-speed airflow over the vehicle generates lift that reduces the contact load on the surface.
- C) 85 N; the normal force must scale up to balance the scalar sum of the vehicle's weight, the downforce, and the horizontal drag force.
- D) 75 N; the normal force acts perpendicular to the surface and increases to balance the sum of the gravitational weight and the downward aerodynamic force, maintaining vertical equilibrium.
5.
An interior painter uses an extension pole to hold a 3.0 kg flat drywall patch stationary against a horizontal ceiling by applying a constant upward vertical force of 45 N. Assuming the patch is in static equilibrium and taking $g = 10\text{ m/s}^2$ , what are the magnitude and direction of the normal force exerted by the ceiling on the drywall patch?
- A) 15 N, directed vertically upward
- B) 15 N, directed vertically downward
- C) 30 N, directed vertically upward
- D) 75 N, directed vertically downward
6.
A laboratory technician pushes two contacting rectangular blocks, Block X of mass 2.0 kg and Block Y of mass 3.0 kg, across a frictionless horizontal bench by applying a constant horizontal force of 25 N directly to Block X. Assuming the blocks remain in contact and taking $g = 10\text{ m/s}^2$ , what are the magnitudes of the horizontal normal force exerted by Block X on Block Y and the vertical normal force exerted by the bench on Block Y?
- A) Horizontal normal force = 25 N; vertical normal force = 50 N
- B) Horizontal normal force = 10 N; vertical normal force = 30 N
- C) Horizontal normal force = 25 N; vertical normal force = 30 N
- D) Horizontal normal force = 15 N; vertical normal force = 30 N
7.
A student investigates how surface orientation influences contact forces by placing a 6.0 kg wooden block at rest on an adjustable inclined ramp. The inclination angle of the ramp relative to the horizontal is initially 0° and is gradually tilted up to 60°. Taking $g = 10\text{ m/s}^2$ and $\cos 60^\circ = 0.50$ , what is the magnitude of the normal force exerted by the ramp on the block at 60°, and why does this normal force decrease as the incline angle increases?
- A) 60 N, because the normal force must always balance the total gravitational force acting on the object.
- B) 52 N, because the ramp must counteract both the gravitational force and impending sliding motion.
- C) 30 N, because the component of gravity perpendicular to the ramp surface decreases as the tilt angle increases.
- D) 30 N, because static friction gradually replaces the normal force as the incline becomes steeper.
8.
A 50 kg student stands on a calibrated scale on the floor of an elevator that is descending toward the ground level. As it approaches its destination, the elevator slows down at a constant rate of $2.0\text{ m/s}^2$ . Taking $g = 10\text{ m/s}^2$ , what is the magnitude of the normal force exerted by the scale on the student, and how does this force compare to the gravitational force acting on the student?
- A) 500 N; it is equal to the gravitational force because the normal force and gravitational force always form an action-reaction pair on horizontal surfaces.
- B) 400 N; it is less than the gravitational force because downward motion always reduces the contact force between a surface and an object.
- C) 100 N; it is less than the gravitational force because the scale only needs to exert the force required to produce the acceleration.
- D) 600 N; it is greater than the gravitational force because an upward net force is required to decelerate the downward motion.
9.
A student presses a 0.5 kg eraser against a flat vertical whiteboard by applying a horizontal pushing force of 15 N directly toward the board, holding the eraser at rest. Which statement correctly identifies the magnitude and direction of the normal force exerted by the whiteboard on the eraser, and describes how this normal force changes if the horizontal push is increased to 25 N while the eraser remains stationary? (Take $g = 10\text{ m/s}^2$ .)
- A) The normal force is 15 N directed horizontally away from the board, and it increases to 25 N when the push is increased.
- B) The normal force is 5 N directed vertically upward, and it remains 5 N because the eraser's mass is unchanged.
- C) The normal force is 15 N directed horizontally away from the board, but it remains constant at 15 N because normal force depends solely on the object's weight.
- D) The normal force is 20 N directed perpendicularly outward, and it increases to 30 N by combining the push with the gravitational force.
10.
A warehouse worker pulls a cargo crate of mass 20 kg across a horizontal concrete floor by exerting a tension force of 50 N through a strap inclined at an angle of 37° above the horizontal. The crate slides forward along the floor without lifting off the ground (take $g = 10\text{ m/s}^2$ , $\sin 37^\circ = 0.60$ , and $\cos 37^\circ = 0.80$ ). What is the magnitude of the normal force exerted by the floor on the crate, and how does it compare to the crate's weight?
- A) 200 N, because the normal force on a horizontal surface must always equal the object's gravitational weight.
- B) 230 N, because the applied pulling force presses the crate harder against the ground by adding its vertical component.
- C) 160 N, because the horizontal component of the tension reduces the contact force exerted by the floor.
- D) 170 N, because the upward vertical component of the tension partially supports the crate's weight.

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