Function transformations and inverses Knowledge-Based Practice

Math · Functions & Trigonometry · Math · Function Fundamentals

5 Math practice questions on Function transformations and inverses. Questions that assess core concepts and understanding.

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Questions

  1. 1.

    Let ff be an invertible function with domain [2,8][2, 8] and range [−1,5][-1, 5]. If g(x)=2f−1(3−x)+1g(x) = 2f^{-1}(3 - x) + 1, what are the domain and range of gg?

    • A) Domain: [−5,1][-5, 1], Range: [5,17][5, 17]
    • B) Domain: [−2,4][-2, 4], Range: [−1,11][-1, 11]
    • C) Domain: [1,7][1, 7], Range: [4,16][4, 16]
    • D) Domain: [−2,4][-2, 4], Range: [5,17][5, 17]
  2. 2.

    Let ff be an invertible function and define g(x)=5−f−1(2x)g(x) = 5 - f^{-1}(2x). Which of the following expressions represents g−1(x)g^{-1}(x) in terms of ff?

    • A) g−1(x)=2f(5−x)g^{-1}(x) = 2f(5 - x)
    • B) g−1(x)=12f(5−x)g^{-1}(x) = \frac{1}{2}f(5 - x)
    • C) g−1(x)=12f(x−5)g^{-1}(x) = \frac{1}{2}f(x - 5)
    • D) g−1(x)=5−12f(x)g^{-1}(x) = 5 - \frac{1}{2}f(x)
  3. 3.

    The graph of the function gg is obtained by reflecting the graph of y=f(3x−12)y = f(3x - 12) across the line y=xy = x, where ff is an invertible function. Which of the following gives g(x)g(x) in terms of f−1(x)f^{-1}(x)?

    • A) g(x)=f−1(13x+4)g(x) = f^{-1}\left(\frac{1}{3}x + 4\right)
    • B) g(x)=3f−1(x)−12g(x) = 3f^{-1}(x) - 12
    • C) g(x)=13f−1(x)−4g(x) = \frac{1}{3}f^{-1}(x) - 4
    • D) g(x)=13f−1(x)+4g(x) = \frac{1}{3}f^{-1}(x) + 4
  4. 4.

    Let ff be an invertible function whose graph contains the point (3,−2)(3, -2). If g(x)=2f(x+1)−4g(x) = 2f(x + 1) - 4, which ordered pair must lie on the graph of y=g−1(x)y = g^{-1}(x)?

    • A) (−8,2)(-8, 2)
    • B) (2,−8)(2, -8)
    • C) (−8,4)(-8, 4)
    • D) (−4,2)(-4, 2)
  5. 5.

    Given the function f(x)=4x−7f(x) = 4x - 7, let g(x)=f(x+13)+2g(x) = f\left(\frac{x+1}{3}\right) + 2. What is the formula for the inverse function g−1(x)g^{-1}(x)?

    • A) g−1(x)=3x−114g^{-1}(x) = \frac{3x - 11}{4}
    • B) g−1(x)=4x+113g^{-1}(x) = \frac{4x + 11}{3}
    • C) g−1(x)=3x+54g^{-1}(x) = \frac{3x + 5}{4}
    • D) g−1(x)=3x+114g^{-1}(x) = \frac{3x + 11}{4}

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