Entropy Knowledge-Based Study

Chemistry · Thermochemistry & Thermodynamics · Chemistry · Entropy & Free Energy

Chemistry topic explanations on Entropy.

Study notes

  1. What is Entropy?

    In thermodynamics, entropy (SS) is a state function that measures the dispersal of energy and matter within a chemical or physical system. While historically described simply as a measure of disorder or randomness, entropy is fundamentally related to the number of microscopic arrangements accessible to a system at a given thermodynamic state.

    Microstates and the Boltzmann Equation

    A microstate (WW) represents a specific arrangement of the positions and kinetic energies of all individual particles in a system. Ludwig Boltzmann formulated the quantitative link between macroscopic entropy and microscopic arrangements:

    S=kBln⁡WS = k_{\text{B}} \ln W

    Here, kBk_{\text{B}} is the Boltzmann constant (1.38×10−23 J/K1.38 \times 10^{-23}\text{ J/K}). As the number of energetically equivalent microstates increases, the dispersal of energy increases, and the entropy of the system rises accordingly.

    Predicting Entropy Changes

    Several physical factors influence the absolute entropy of a substance:

    • Physical State (Phase): For a given substance, entropy increases significantly across phase transitions:
      S(solid)<S(liquid)≪S(gas)S(\text{solid}) < S(\text{liquid}) \ll S(\text{gas})Particles in a solid vibrate around fixed lattice positions, whereas gas molecules move independently throughout the entire volume, dramatically increasing accessible microstates.
    • Temperature: Raising temperature increases the average kinetic energy of particles and broadens the distribution of molecular speeds, which increases the number of available energy states and thus increases entropy.
    • Volume and Pressure (for Gases): Expanding a gas into a larger volume at constant temperature provides more spatial microstates, leading to an increase in entropy (ΔS>0\Delta S > 0). Conversely, compressing a gas decreases entropy.
    • Molecular Complexity: For different substances in the same phase, molecules with more atoms or more flexible structures possess greater rotational and vibrational degrees of freedom, giving them higher standard molar entropies.

    The Third Law of Thermodynamics

    The Third Law of Thermodynamics states that the entropy of a pure, perfectly ordered crystalline substance at absolute zero (0 K0\text{ K}) is exactly zero:

    S(0 K)=0 J/(mol⋅K)S(0\text{ K}) = 0\text{ J}/(\text{mol}\cdot\text{K})

    Because there is an absolute zero reference point for entropy, unlike enthalpy, we can determine the absolute standard molar entropy (S∘S^\circ) for any substance at standard conditions (298.15 K298.15\text{ K} and 1 bar1\text{ bar}). Consequently, standard molar entropies are always positive values.

    Calculating Standard Entropy of Reaction

    The standard entropy change of a chemical reaction (ΔSrxn∘\Delta S^\circ_{\text{rxn}}) is determined by subtracting the standard entropies of the reactants from those of the products, each multiplied by their stoichiometric coefficients:

    ΔSrxn∘=∑n S∘(products)−∑m S∘(reactants)\Delta S^\circ_{\text{rxn}} = \sum n\,S^\circ(\text{products}) - \sum m\,S^\circ(\text{reactants})

    The Second Law of Thermodynamics

    The Second Law of Thermodynamics governs whether a process can occur spontaneously. It states that for any spontaneous (irreversible) process, the total entropy of the universe must increase:

    ΔSuniv=ΔSsys+ΔSsurr>0\Delta S_{\text{univ}} = \Delta S_{\text{sys}} + \Delta S_{\text{surr}} > 0

    A process where ΔSsys<0\Delta S_{\text{sys}} < 0 can still occur spontaneously if it transfers enough heat to the surroundings to produce a sufficiently positive ΔSsurr\Delta S_{\text{surr}}.

    Entropy Changes in the Surroundings

    At constant temperature and pressure, heat exchanged by the system enters or leaves the surroundings reversibly, yielding:

    ΔSsurr=−ΔHsysT\Delta S_{\text{surr}} = -\frac{\Delta H_{\text{sys}}}{T}

    An exothermic process (ΔHsys<0\Delta H_{\text{sys}} < 0) releases heat to the surroundings, increasing ΔSsurr\Delta S_{\text{surr}}. An endothermic process (ΔHsys>0\Delta H_{\text{sys}} > 0) absorbs heat from the surroundings, decreasing ΔSsurr\Delta S_{\text{surr}}.

    Predicting the Sign of ΔSsys∘\Delta S^\circ_{\text{sys}}

    In chemical reactions, the sign of ΔSsys∘\Delta S^\circ_{\text{sys}} is predominantly determined by changes in the number of moles of gas (Δngas\Delta n_{\text{gas}}):

    Δngas=∑ngas(products)−∑ngas(reactants)\Delta n_{\text{gas}} = \sum n_{\text{gas}}(\text{products}) - \sum n_{\text{gas}}(\text{reactants})

    • If Δngas>0\Delta n_{\text{gas}} > 0, the reaction produces net gas molecules, so ΔSsys∘>0\Delta S^\circ_{\text{sys}} > 0.
    • If Δngas<0\Delta n_{\text{gas}} < 0, gas molecules are consumed, resulting in ΔSsys∘<0\Delta S^\circ_{\text{sys}} < 0.
    • If Δngas=0\Delta n_{\text{gas}} = 0, the entropy change is generally small, and its sign depends on differences in molecular complexity or phase changes among nongaseous components.

    Example Reaction

    Consider the synthesis of ammonia:
    N2(g)+3H2(g)ightarrow2NH3(g)\text{N}_2(\text{g}) + 3\text{H}_2(\text{g}) ightarrow 2\text{NH}_3(\text{g})

    Here, 4 mol4\text{ mol} of gas reactants yield 2 mol2\text{ mol} of gas product (Δngas=2−4=−2\Delta n_{\text{gas}} = 2 - 4 = -2). Because gas particles are combined into fewer molecules, the number of translational microstates decreases, giving ΔSsys∘<0\Delta S^\circ_{\text{sys}} < 0.