PH and pOH Knowledge-Based Study

Chemistry · Acids & Bases · Chemistry · Acid–Base Concepts

Chemistry topic explanations on PH and pOH.

Study notes

  1. The pH scale provides a convenient logarithmic method to express the hydronium ion concentration, [H3O+][\text{H}_3\text{O}^+], in an aqueous solution.

    Mathematical Definition

    pH is defined as the negative base-10 logarithm of the hydronium ion concentration:

    pH=−log⁡[H3O+]\text{pH} = -\log[\text{H}_3\text{O}^+]

    Because the scale is logarithmic, each whole pH unit represents a tenfold change in hydronium ion concentration:

    • A solution with pH=3\text{pH} = 3 has 10 times the hydronium ion concentration of a solution with pH=4\text{pH} = 4.
    • A solution with pH=2\text{pH} = 2 has 100 times the hydronium ion concentration of a solution with pH=4\text{pH} = 4.

    Similar to pH, pOH expresses the alkalinity or hydroxide ion concentration, [OH−][\text{OH}^-], of an aqueous solution.

    Mathematical Definition

    pOH is defined as the negative base-10 logarithm of the hydroxide ion concentration:

    pOH=−log⁡[OH−]\text{pOH} = -\log[\text{OH}^-]

    Key characteristics of the pOH scale include:

    • A smaller pOH value indicates a higher concentration of hydroxide ions, meaning the solution is more basic.
    • A larger pOH value indicates a lower concentration of hydroxide ions.

    Pure water undergoes autoionization to a small extent:

    2H2O(l)⇌H3O+(aq)+OH−(aq)2\text{H}_2\text{O}(l) \rightleftharpoons \text{H}_3\text{O}^+(aq) + \text{OH}^-(aq)

    At 25 °C, the ion-product constant for water (KwK_w) is constant:

    Kw=[H3O+][OH−]=1.0×10−14K_w = [\text{H}_3\text{O}^+][\text{OH}^-] = 1.0 \times 10^{-14}

    Taking the negative logarithm of both sides yields the interconversion equation:

    pH+pOH=14.00(at 25 ∘C)\text{pH} + \text{pOH} = 14.00 \quad (\text{at } 25\ ^\circ\text{C})

    Classification of Solutions at 25 °C

    • Acidic: [H3O+]>[OH−][\text{H}_3\text{O}^+] > [\text{OH}^-], resulting in pH<7.00\text{pH} < 7.00 and pOH>7.00\text{pOH} > 7.00.
    • Neutral: [H3O+]=[OH−]=1.0×10−7 M[\text{H}_3\text{O}^+] = [\text{OH}^-] = 1.0 \times 10^{-7}\text{ M}, resulting in pH=7.00\text{pH} = 7.00 and pOH=7.00\text{pOH} = 7.00.
    • Basic: [OH−]>[H3O+][\text{OH}^-] > [\text{H}_3\text{O}^+], resulting in pH>7.00\text{pH} > 7.00 and pOH<7.00\text{pOH} < 7.00.

    When the pH or pOH of a solution is known, the respective ion concentrations can be determined using the inverse logarithm (powers of 10):

    • [H3O+]=10−pH[\text{H}_3\text{O}^+] = 10^{-\text{pH}}
    • [OH−]=10−pOH[\text{OH}^-] = 10^{-\text{pOH}}

    Summary of Four-Way Interconversions

    Given any one of [H3O+][\text{H}_3\text{O}^+], [OH−][\text{OH}^-], pH\text{pH}, or pOH\text{pOH}, the other three values can be found using these key relationships:

    1. pH=−log⁡[H3O+]\text{pH} = -\log[\text{H}_3\text{O}^+] and [H3O+]=10−pH[\text{H}_3\text{O}^+] = 10^{-\text{pH}}
    2. pOH=−log⁡[OH−]\text{pOH} = -\log[\text{OH}^-] and [OH−]=10−pOH[\text{OH}^-] = 10^{-\text{pOH}}
    3. pH+pOH=14.00\text{pH} + \text{pOH} = 14.00 (at 25 °C)
    4. [H3O+][OH−]=1.0×10−14[\text{H}_3\text{O}^+][\text{OH}^-] = 1.0 \times 10^{-14} (at 25 °C)